Please write a program which asks the user to type in a string. The program then prints out all the substrings which begin with the first character, from the shortest to the longest. Have a look at the example below.
Please type in a string: test
t
te
tes
test
Obviously my code is not the way it supposed to be:
stg = input("Please type in a string: ")
print(stg[0])
print(stg[0:5])
print(stg[0:10])
print(stg[10:50])
print(stg[:])
ok, this is a homework and I don't give you the exact solution... but as some points:
loop you need to know about string length and use a builtin method for getting the length...any question? ask it...
userString = input("Gimme String: ")
# Looping based on the given String
# Last Value is not included so you need to increment the value by one
for i in range(len(userString)):
# Last Value is not included so you need to increment the value by one
print(userString[:i+1])
#Alternative
for i in range(1,len(userString)+1):
print(userString[:i])
Please type in a string: test t st est test
[:ì] of the alternative implementation in the slice with [:i*-1]Gimme String: test tes te tstg = input("Please type in a string: ")
print("\n".join([stg[0:i+1] for i in range (len(stg))]))
Output:
t
te
tes
test
Just use simple for loop
stg = 'test'
temp_str = ''
for i in range(len(stg)):
temp_str = temp_str + stg[i]
print(temp_str)
SANJU in variable string. Now in order to get the first element of my name, S, you need to use indexing. Thus, string[0] would give us S and string[1] would give us A and so on. That is what I am doing above. Getting all the string elements fromstg though indexing. i stores the value of 0,1,2,3, which we are getting by applying range () function on the total length of the string.stg = 'test' for i in range(1,len(stg)+1): print(stg[ -i:])input_str1 = input("Please type in a string: ")
i = 0
while i < len(input_str1):
print(input_str1[0:i+1])
i+=1
