insert argument to map function python [duplicate]

Question

I have a following function:

def calculate_frequent_itemset(fractional_data, support):
    """Function that calculated the frequent dataset parallely"""
    return apriori(fractional_data, min_support=support, use_colnames=True)

I would like to call it in a map function using:

frequent_itemsets=p.map(calculate_frequent_itemset,(dataNew1,dataNew2,dataNew3,dataNew4,dataNew5), 200)

In other words I want to set 200 as support argument. But I got an error TypeError: calculate_frequent_itemset() missing 1 required positional argument: 'support'. How can I fix it please?

Also: stackoverflow.com/q/10834960/10197418

FObersteiner
– FObersteiner

2021-11-10 09:56:53 +00:00
Commented Nov 10, 2021 at 9:56 — FObersteiner
– FObersteiner, Commented Nov 10, 2021 at 9:56

jtlz2 · Accepted Answer · 2021-11-10 12:02:32Z

0

You could use a wrapper function (or a lambda):

support=200
def my_calculate_frequent_itemset(fractional_data):
    return calculate_frequent_itemset(fractional_data, support)

frequent_itemsets=p.map(my_calculate_frequent_itemset,(dataNew1,dataNew2,dataNew3,dataNew4,dataNew5))

It's pretty horrible.

I rediscovered this - rather perhaps see https://stackoverflow.com/a/31995624/1021819 which gives the same answer

edited Nov 10, 2021 at 12:02

answered Nov 10, 2021 at 9:57

jtlz2

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3 Comments

vojta Over a year ago

Does not work, same error.

jtlz2 Over a year ago

@vojta stackoverflow.com/a/31995624/1021819 does not work for you?

jtlz2 Over a year ago

@MrFuppes Edited to remove lambda (no longer seems elegant / worth it..)

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