Why does the code below return the error "SyntaxError: invalid syntax"
If(amount_paid==12):
I know it's basic but just starting out learning Python in Visual Studio Code
Thanks for any help,
Phil
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Python is case sensitivejuanpa.arrivillaga– juanpa.arrivillaga2020-05-29 02:07:50 +00:00Commented May 29, 2020 at 2:07
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@Nick almost certainly... i can't find a good duplicate at the moment, but I'm on my phone so please feel free to offer up a good onejuanpa.arrivillaga– juanpa.arrivillaga2020-05-29 02:13:35 +00:00Commented May 29, 2020 at 2:13
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Fixed! Sorry, didn't notice the upper Case I in the if keyword, thanks for the help.Philip Black– Philip Black2020-05-29 02:17:34 +00:00Commented May 29, 2020 at 2:17
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Does this answer your question? Invalid syntax---pythonJaydeep– Jaydeep2020-05-29 02:23:21 +00:00Commented May 29, 2020 at 2:23
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@juanpa.arrivillaga there's a couple there nowNick– Nick2020-05-29 02:26:56 +00:00Commented May 29, 2020 at 2:26
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3 Answers
Most things in Python are case-sensitive. Here, that's the if construct -- If amount_paid == 12: is not well formed, but if amount_paid == 12: is.
3 Comments
juanpa.arrivillaga
python, in general, is case-sensitive.
Seabody
Good point, will edit my answer.
Philip Black
Fixed! Sorry, didn't notice the upper Case I in the if keyword, thanks for the help.
Try making If lowercase (make the "I" lowercase)
1 Comment
Philip Black
Fixed! Sorry, didn't notice the upper Case I in the if keyword, thanks for the help.
- The issue in the upper case "If". Change to "if"
- Parentheses are not mandatory, although, they should not affect anything in your case:
if amount_paid == 12: