How to get parameters from URL in python flask [duplicate]

Question

I have following codes:

<tr>
  <td>{{ q.title }}</td>                    
  <td>{{ q.text }}</td>
  <td><a href="http://localhost:8000/answer?t={{ q.title }}"> Answer </a></td>
</tr>

and in the flask I have this code:

@app.route("/answer" , methods=['GET'])
   def answer():
      atitle = request.args.get('t')
      return render_template('answer.html' , value=atitle)

I tried differend ways and also used:

@app route("/answer/<t>" , methods=['GET'])

but none of them is working and I keep recieving "GET /answer/Java HTTP/1.1" 404

are you sure your url encoding is correct? Can you print the url on console before making the request — mad_
– mad_, Commented Sep 11, 2018 at 20:44

dekim · Accepted Answer · 2018-09-11 20:46:26Z

0

I suspect you've got something else running on port 8000 and flask is listening on a different port (likely 5000). Try using url_for instead of constructing the url yourself...

<a href="{{ url_for('.answer', t=q.title) }}">Answer</a>

See http://flask.pocoo.org/docs/1.0/api/?highlight=url_for#flask.url_for

answered Sep 11, 2018 at 20:46

dekim

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