Given an array of arrays, for each inner array - If the array has < 2 numbers, return 0 else return second smallest number [duplicate]

I searched there a few times but came across nothing specifically with this. I have completed this question and here is my code;

int[][] input = {{0}, {0,1}, {4,3,2,1}, {32, 56, 67, 98, 97,8888, 35}};

    for(int row = 0; row<input.length; row++) {
    Arrays.sort(input[row]);
    for(int col = 0; col<input[row].length; col++) {
        if (input[row].length < 2) {
            System.out.print(0 + " ");
        } else {
            System.out.print(input[row][1] + " ");
            break;
        }
    }
    }

Why I felt the need to post this is to simply inquire, is there a better and more efficient way to answer this question? I simply sorted my arrays and printed the first element which would be the second smallest number. But I am thinking about a better way to complete this question if there were millions of records?