Storing digits of numbers in array

Question

Hello fellow programmers ! I am a beginner with Java and i am looking for a method or a way maybe to store the digits of a 6 digit number entered by the user , in an int array. For example :- if the number is 675421. then i want to store the digits in an array like :-

int[] array = new int[6];
int number = 675421 
array[0] = 6;
array[1] = 7;
array[2] = 5; 
array[3] = 4;
array[4] = 2;
array[5] = 1;

I want to do so so that i can work with the array to maybe sort or change the order or numbers in array. Thanks!

Possible duplicate of How to split an Integer into an Array using Java? — sinclair
– sinclair, Commented Jan 30, 2016 at 18:37
Oh im really sorry if it is a duplicate....its just that i didnt quite understand what to do in this case . so if anyone can explain to me the thing to be done and the logic behind it ? — m0mosenpai
– m0mosenpai, Commented Jan 30, 2016 at 18:42
My question is how to reproduce such an array from a given number or a number entered by the user. I want to separately store the digits in a array — m0mosenpai
– m0mosenpai, Commented Jan 30, 2016 at 18:43

Let'sRefactor · Accepted Answer · 2016-01-30 19:09:19Z

4

Here you go,

String temp = Integer.toString(number);

int[] num = new int[temp.length()];

for (int i = 0; i < temp.length(); i++){
    num[i] = temp.charAt(i) - '0';
}

for (int i = 0; i < temp.length(); i++) {
    System.out.println(num[i]);
}

Edit, after comment

Here, First, you are converting to your number to a string. Then, take each char out of it(in the loop), subtract the ASCII value of 0 from each char to get the digit [ie, ASCII of 0 is 48, 1 is 49, ... ] (see ASCII table)

edited Jan 30, 2016 at 19:09

answered Jan 30, 2016 at 18:43

Let'sRefactor

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2 Comments

m0mosenpai Over a year ago

Thanks ! can u explain me the line within the first for loop?

Let'sRefactor Over a year ago

Answer Updated, hope it helps you.

asdfasdfadsf · Accepted Answer · 2016-01-30 18:47:07Z

2

Do something like this:

String number = "123123";
    int[] intArray = new int[number.length()];

    for (int i = 0; i < number.length(); i++)
    {
        intArray[i] = Integer.parseInt(Character.toString(number.charAt(i)));
    }

Hope this helps,

Jason.

answered Jan 30, 2016 at 18:47

asdfasdfadsf

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Comments

Tarun Jain · Accepted Answer · 2018-03-21 14:27:12Z

1

Below is the recursive solution

public static void main(String[] args) {
    int testNum = 675421;
    List<Integer> digitList = new ArrayList<Integer>();
    collectDigits(testNum, digitList);
    Object[] resultArr = digitList.toArray();
    int listSize = resultArr.length;
    for (int listCount = 0; listCount < listSize; listCount++) {
        System.out.println("result["+listCount+"] = "+resultArr[listCount]);
    }
}

private static void collectDigits(int num, List<Integer> digits) {
    if (num / 10 > 0) {
        collectDigits(num / 10, digits);
    }
    digits.add(num % 10);
}

edited Mar 21, 2018 at 14:27

user8280225

answered Jan 30, 2016 at 19:20

Tarun Jain

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2 Comments

m0mosenpai Over a year ago

A bit complicated for me but thanks anyways. Appreciate the help.

Tarun Jain Over a year ago

I have divided the number by 10, store the remainder in an array, call collectDigits function with quotient as the new number

Jake H. · Accepted Answer · 2016-01-30 18:46:42Z

0

One way to do this would be to turn the original integer into a string. Loop over the string, parsing each character back to an int, and place into the array. Here is an example:

int number = 123456;

String strNumber = number+"";

int[] array = new int[strNumber.length()];

int index = 0;

for(char c : strNumber.toCharArray()){
    array[index++] = Integer.parseInt(c+"");
}

System.out.println(Arrays.toString(array));

answered Jan 30, 2016 at 18:46

Jake H.

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Comments

Andrea Catania · Accepted Answer · 2016-01-30 18:59:25Z

0

Math solution, you can split the int number using this:

int[] array = new int[6];
int number = 675421;
array[0] = ((number/100000)%10);
array[1] = ((number/10000)%10);
array[2] = ((number/1000)%10);
array[3] = ((number/100)%10);
array[4] = ((number/10)%10);
array[5] = ((number/1)%10);

If the "number" has a variable length you can automate this, write a coment if you need help

answered Jan 30, 2016 at 18:59

Andrea Catania

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