In PHP, how would one check to see if a specified item (by name, I think - number would probably also work) in an array is empty?
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4 Answers
Types of empty (from PHP Manual). The following are considered empty for any variable:
- "" (an empty string)
- 0 (0 as an integer)
- "0" (0 as a string)
- NULL
- FALSE
- array() (an empty array)
- var $var; (a variable declared, but without a value in a class)
So take the example below:
$arr = array(
'ele1' => 'test',
'ele2' => false
);
1) $arr['ele3'] is not set. So:
isset($arr['ele3']) === false && empty($arr['ele3']) === true
it is not set and empty. empty() checks for whether the variable is set and empty or not.
2) $arr['ele2'] is set, but empty. So:
isset($arr['ele2']) === true && empty($arr['ele2']) === true
1) $arr['ele1'] is set and not empty:
isset($arr['ele1']) === true && empty($arr['ele1']) === false
if you wish to check whether is it empty, simply use the empty() function.
1 Comment
Nathaniel
Oooh, helpful. I would upvote you guys if I had enough rep. Heh.
if(empty($array['item']))
or
if(!isset($array['item']))
or
if(!array_key_exists('item', $array))
depending on what precisely you mean by "empty". See the docs for empty(), isset() and array_key_exists() as to what exactly they mean.
<?php
$myarray=array(1,5,6,5);
$anotherarray=array();
function checkEmpty($array){
return (count($array)>0)?1:0;
}
echo checkEmpty($myarray);
echo checkEmpty($anotherarray);
?>
(for checking if empty result 1 else 0);
Compactness is what I persue in my code.
Comments
i had such situation where i was getting tab it last index of array so if put things together then this might work for the most of cases
<?php
if( ctype_space($array['index']) && empty($array['index']) && !isset($array['index']) ){
echo 'array index is empty';
}else{
echo 'Not empty';
}
