Summary: in this tutorial, you will learn how to use the SQLite json_type() function to return the type of a JSON element.
Introduction to the SQLite json_type() function
In SQLite, the json_type() function returns the type of a JSON element. Here’s the syntax of the json_type() function:
json_type(x)Code language: SQL (Structured Query Language) (sql)In this syntax:
xis the JSON element of which you want to get the type.
If you want to get the JSON type of an element specified by a path, you can use the following syntax:
json_type(x, path)Code language: SQL (Structured Query Language) (sql)In this syntax, the json_type() function returns the type of the element in x selected by the path.
The json_type() function returns the following SQL text values:
- null
- false
- true
- integer
- real
- text
- array
- object
If the path does not exist in x, then the json_type() function returns NULL.
SQLite json_type() function examples
The following example uses the json_type() function to return the json type of a JSON object:
SELECT json_type('{"name": "Joe"}');Code language: SQL (Structured Query Language) (sql)Output:
json_type('{"name": "Joe"}')
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objectCode language: SQL (Structured Query Language) (sql)The following example uses the json_type() function to return the json type of a JSON array:
SELECT json_type('[1,2,3]');Code language: SQL (Structured Query Language) (sql)Output:
json_type('[1,2,3]')
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arrayCode language: SQL (Structured Query Language) (sql)The following example uses the json_type() function to return the json type of the first element in a JSON array:
SELECT json_type('[1,2,3]', '$[1]');Code language: SQL (Structured Query Language) (sql)Output:
json_type('[1,2,3]', '$[1]')
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integerCode language: SQL (Structured Query Language) (sql)The following example uses the json_type() function to return the json type of the value of the name property in a JSON object:
SELECT json_type('{"name": "Joe"}','$.name');Code language: SQL (Structured Query Language) (sql)Output:
json_type('{"name": "Joe"}','$.name')
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textCode language: SQL (Structured Query Language) (sql)The following example uses the json_type() function to return the json type of the value of the active property in a JSON object:
SELECT json_type('{"name": "Joe", "active": true }','$.active');Code language: SQL (Structured Query Language) (sql)Output:
json_type('{"name": "Joe", "active": true }','$.active')
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trueCode language: SQL (Structured Query Language) (sql)The following example uses the json_type() function to return the json type of the value of a property that does not exist:
SELECT json_type('{"name": "Joe"}','$.age');Code language: SQL (Structured Query Language) (sql)Output:
json_type('{"name": "Joe"}','$.age')
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nullCode language: SQL (Structured Query Language) (sql)The following statement uses the json_type() function to return the json type of the value of the age property:
SELECT json_type('{"name": "Joe", "age": 25}','$.age');Code language: SQL (Structured Query Language) (sql)Output:
json_type('{"name": "Joe", "age": 25}','$.age')
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integerCode language: SQL (Structured Query Language) (sql)The following statement uses the json_type() function to return the json type of the value of the weight property:
SELECT json_type('{"name": "Joe", "age": 25, "weight": 176.37}','$.weight');Code language: SQL (Structured Query Language) (sql)Output:
json_type('{"name": "Joe", "age": 25, "weight": 176.37}','$.
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realCode language: SQL (Structured Query Language) (sql)Summary
- Use the
json_type(x)function to get the JSON type of the outermost element of x. - Use the
json_type(x, path)function to obtain the JSON type of the element in x specified by the path.