PHP & JSON - Accessing Data

Question

I'm building a JSON array as follows:

 $footerSEOArray[$data['domainname']] = $data[$language];
 echo json_encode($footerSEOArray);

Once passed back I decode it like this:

 $footerLinks = json_decode($result);

I can print the array as follows:

 print_r($footerLinks);

And when printed it looks like this:

    stdClass Object
 (
[www.data1.com] => Australia
[www.data2.com] => Hindu
[www.data3.com] => Laos
[www.data4.com] => Iranian
[www.data5.com] => America
)

Now I need to be able to print the first and second parts of the array but I can't seem to get it to print outside of the print_r();

thx

It is an object not an array. you should learn how to access object property or array items. — Shakti Singh
– Shakti Singh, Commented Jan 2, 2012 at 12:03
$footerLinks is an object. You probably want to get it as array, for which you have to pass true as second parameter to json_decode. You can then iterate over the array. — Felix Kling
– Felix Kling, Commented Jan 2, 2012 at 12:04
You should be using echo $footerLinks[0]->{'www.data1.com'}; — dkulkarni
– dkulkarni, Commented Jan 2, 2012 at 12:08

Eineki · Accepted Answer · 2012-01-02 12:08:21Z

1

You have to pass to json_decode an additional parameter to obtain an array instead that a generic array.

 $footerLinks = json_decode($result, true);

Reference: The php manual json_decode page

answered Jan 2, 2012 at 12:08

Eineki

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hamczu · Accepted Answer · 2012-01-02 12:07:04Z

1

You should pass the second parameter to the json_decode function. It's default behaviour is to convert key-value pairs to the stdClass object, but with this parameter you force using associative table instead.

So:

 $footerLinks = json_decode($result, true);

answered Jan 2, 2012 at 12:07

hamczu

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Sudhir Bastakoti · Accepted Answer · 2012-01-02 12:02:31Z

0

Try:


$footerLinks = (array) $footerLinks;

answered Jan 2, 2012 at 12:02

Sudhir Bastakoti

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vkGunasekaran · Accepted Answer · 2012-01-02 13:11:00Z

0

As all said $footerlinks is an object , if you want to use it like an array you've to decode like this:

 $footerLinks = json_decode($result,true);

Now, $footLinks becomes an associative array.

answered Jan 2, 2012 at 13:11

vkGunasekaran

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