I have an array that contains some of these 3 values: ['daily', 'monthly', 'yearly']
but sometimes the array only contains: ['monthly', 'daily']
and what I want is to get the minimum between these 3 values which is daily and if not there I want monthly and also if it's not there I want the yearly. How can I achieve that ?
You can approach this issue by comparing the values daily, monthly, and yearly alphabetically/by ASCII order
string1.localeCompare(string2): returns -1 if smaller, 1 if bigger, and 0 if equal. use it while iterating through the array. If your array could contain only those 3 values, just use : array.includes('daily')Simplest approach that doesn't rely on alphabetic ordering (and would therefore still work when adding new intervals like hourly):
function getLowest (arr) {
const order = ['daily', 'monthly', 'yearly']
return order.find(val => arr.includes(val))
}
This works because find will return the first matching result.
Here's a simple one-liner function:
const arr1 = ['daily', 'monthly', 'yearly'], arr2 = ['monthly', 'yearly'], arr3 = ['yearly'], [d,m,y] = arr1;
const lowestVal = (arr) => arr.find(x => x===d) ?? arr.find(x => x===m) ?? y;
console.log(lowestVal(arr1));
console.log(lowestVal(arr2));
console.log(lowestVal(arr3));Here is the function you just need to pass your array it will return a minimum value.
function getMinimum(arr)
{
return arr.includes('daily') ? 'daily' : arr.includes('monthly') ? 'monthly' : arr.includes('yearly') ? 'yearly' : "";
}
var arr1 = ['daily', 'monthly', 'yearly'];
console.log(getMinimum(arr1));
if (array.includes('daily')) { /* DAILY */ } else if (array.includes('monthly')) { /* MONTHLY */ } else { /* YEARLY */ }