This is my JSON file output:
let employees = [{
"id":1,
"name":"Lann",
"username":"brot",
"email":"[email protected]",
"address": {
"city":"Gweh",
"zipcode":"92998-3874",
"geo": {
"lat":"45",
"lng":"77"
}
}
}]
How I get id, name and email from that like below:
{
"id":1,
"name":"Lann",
"email":"[email protected]"
}
If your array has only one element you can just access the info, no need to build another array like this: employees[0].id , employees[0].name, employees[0].email or you can just extract an object using Object Destructuring
let employees = [{
"id": 1,
"name": "Lann",
"username": "brot",
"email": "[email protected]",
"address": {
"city": "Gweh",
"zipcode": "92998-3874",
"geo": {
"lat": "45",
"lng": "77"
}
}
}];
const picked = (({ id, name, email }) => ({ id, name, email }))(employees[0]);
console.log(picked);but if your array has more employees, i think what you need to do is search by id or name and get back just an object with minimal info, you can do that like this
let employees = [{
"id": 1,
"name": "Lann",
"username": "brot",
"email": "[email protected]",
"address": {
"city": "Gweh",
"zipcode": "92998-3874",
"geo": {
"lat": "45",
"lng": "77"
}
}
}];
let employee = employees.find(o => o.name === 'Lann');
let picked = (({ id, name,email }) => ({ id, name,email }))(employee);
console.log(picked);You can archive using map.
let employees = [{
"id":1,
"name":"Lann",
"username":"brot",
"email":"[email protected]",
"address":{
"city":"Gweh",
"zipcode":"92998-3874",
"geo":{
"lat":"45",
"lng":"77"
}
}
}]
const data = employees.map(o => ({ id: o.id, name: o.name, email:o.email }));
console.log(data[0]);
let employees = [{
"id":1,
"name":"Lann",
"username":"brot",
"email":"[email protected]",
"address":{
"city":"Gweh",
"zipcode":"92998-3874",
"geo":{
"lat":"45",
"lng":"77"
}
}}];
// Destructuring array
const [employee] = employees;
employee is an object and you can access its property normally as you do with other objects. For getting id, name, username:**employee.id;
employee.name;
employee.username;
You cans also loop through your input if it contains multiple items and get an array of shrink items :
let employees = [{
"id": 1,
"name": "Lann",
"username": "brot",
"email": "[email protected]",
"address": {
"city": "Gweh",
"zipcode": "92998-3874",
"geo": {
"lat": "45",
"lng": "77"
}
}
}]
let shrink = [];
for (let employee of employees) {
shrink.push({
id: employee.id,
name: employee.name,
email: employee.email
});
}
console.log(shrink);
}, ie}]should be}}]Whith a correct input, you canconsole.log(employees[0].name);for example.