Python/Numpy: Combining boolean masks by row in 2D array

Question

I have a 2D numpy array of boolean masks with n rows where each row is an array of m masks.

maskArr = [
            [[True, False, True, False], [True, True, False, True], [True, True, False, True]],
            [[False, True, False, True], [False, True, True, True], [True, True, False, True]],
            [[True, False, True, False], [True, True, False, True], [True, True, False, True]],
            [[False, True, False, True], [False, True, True, True], [True, True, False, True]],
            [[True, False, True, False], [True, True, False, True], [True, True, False, True]],
            [[False, True, False, True], [False, True, True, True], [True, True, False, True]]
          ]

Is there a way to vectorize the combining of mask arrays in each row to get the following result?

combinedMaskArr = [
                    [True, False, False, False],
                    [False, True, False, True],
                    [True, False, False, False],
                    [False, True, False, True],
                    [True, False, False, False],
                    [False, True, False, True]
                  ]

Thank you for any guidance or suggestions in advance.

seems you want to apply "AND" operations on each triplet of corresponding values. Look for "all" in numpy — Pac0
– Pac0, Commented May 26, 2021 at 10:30

Reti43 · Accepted Answer · 2021-05-26 10:29:35Z

3

You're trying to testing whether all elements are true along a specific axis. Use np.all

np.all(maskArr, axis=1)

Output

array([[ True, False, False, False],
       [False,  True, False,  True],
       [ True, False, False, False],
       [False,  True, False,  True],
       [ True, False, False, False],
       [False,  True, False,  True]])

answered May 26, 2021 at 10:29

Reti43

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