Complete missing sequence in array with zeros in javascript

Question

I have the following array:

const arr = [
  [5, 0.2],
  [7, 0.6],
  [8, 0.3],
  [10, 0.4]
];

console.log(arr)

I need to ensure that the first element of the array is a sequence from 5 to 10:

[5, 6, 7, 8, 9, 10]

In the above example, these numbers within the sequence are missing:

[6, 9]

If they are missing, I need to include them with zeros:

const expectedResult = [
  [5, 0.2],
  [6, 0],
  [7, 0.6],
  [8, 0.3],
  [9, 0],
  [10, 0.4]
];

console.log(expectedResult)

Any ideas on how to achieve this?

Is the sequence range known?

thgaskell
– thgaskell

2021-04-21 08:52:55 +00:00
Commented Apr 21, 2021 at 8:52 — thgaskell
– thgaskell, Commented Apr 21, 2021 at 8:52
yes, from 5 to 10

FMM
– FMM

2021-04-21 08:58:16 +00:00
Commented Apr 21, 2021 at 8:58 — FMM
– FMM, Commented Apr 21, 2021 at 8:58

Nina Scholz · Accepted Answer · 2021-04-21 09:10:07Z

4

You could map the missing parts with a closure over the actual index of the given array.

const
    array = [[5, 0.2], [7, 0.6], [8, 0.3], [10, 0.4]],
    result = Array.from(
        { length: 6 },
        (i => (_, j) => array[i]?.[0] === j + 5 ? array[i++] : [j + 5, 0])(0)
    );

console.log(result);

edited Apr 21, 2021 at 9:10

answered Apr 21, 2021 at 8:53

Nina Scholz

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1 Comment

Nina Scholz Over a year ago

@thgaskell, no, because found, it should increment to get the next element in the next loop.

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