Problem filtering the minimum value of an array at the array input in JavaScript [duplicate]

Question

I wanted the food with the lowest price to be displayed on the console, but my code does not work. Thank you for helping me get the correct code.

Give me the output I want : name : Berger price : 23.83

let menu = [
    { id: 1, name: "Soda", price: 3.12, size: "4oz", type: "Drink" },
    { id: 2, name: "Beer", price: 6.50, size: "8oz", type: "Drink" },
    { id: 3, name: "Margarita", price: 12.99, size: "12oz", type: "Drink" },
    { id: 4, name: "Pizza", price: 25.10, size: "60oz", type: "Food" },
    { id: 5, name: "Kebab", price: 31.48, size: "42oz", type: "Food" },
    { id: 6, name: "Berger", price: 23.83, size: "99oz", type: "Food" },
];

const cheap_food = () => {
    const cheap = menu.filter(menuItem => menuItem.price > 0 && menuItem.type === "Food");
    cheap.forEach(price => console.log(Math.min(price)));
}
cheap_food();

Lakshya Thakur · Accepted Answer · 2021-03-05 14:48:33Z

2

Destructure the price from each menuItem object that you're getting. Even after filter, the cheap array is an array of objects and not just price values. With your updated question, following will work :-

let menu = [
    { id: 1, name: "Soda", price: 3.12, size: "4oz", type: "Drink" },
    { id: 2, name: "Beer", price: 6.50, size: "8oz", type: "Drink" },
    { id: 3, name: "Margarita", price: 12.99, size: "12oz", type: "Drink" },
    { id: 4, name: "Pizza", price: 25.10, size: "60oz", type: "Food" },
    { id: 5, name: "Kebab", price: 31.48, size: "42oz", type: "Food" },
    { id: 6, name: "Berger", price: 23.83, size: "99oz", type: "Food" },
];


const cheap_food = () => {
    const cheap = menu.filter(menuItem => menuItem.price > 0 && menuItem.type === "Food");
        const item = cheap.sort((itemA,itemB)=>itemA.price-itemB.price)[0];
        console.log(`${item.name} price : ${item.price}`);
}
cheap_food();

edited Mar 5, 2021 at 14:48

answered Mar 5, 2021 at 14:33

Lakshya Thakur

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6 Comments

Amir7222 Over a year ago

This is not my answer My desired result name : Berger price : 23.83

Lakshya Thakur Over a year ago

@Amir7222 Seems you updated your question.

Amir7222 Over a year ago

Yes, please help me to reach a conclusion

Lakshya Thakur Over a year ago

@Amir7222 The above can be done with .forEach as well. It's just .sort seemed cleaner to me.

Lakshya Thakur Over a year ago

const item = cheap.sort((itemA,itemB)=>itemA.price-itemB.price)[cheap.length-1]. Our sort implementation returns an array where elements are sorted in increasing order. So first element (index = 0) is smallest and last element (index = length of array - 1) is the greatest.

|

FloWy · Accepted Answer · 2021-03-05 14:33:57Z

0

Just use price.price instead of only price. The reason for that is that the filter function returns the filtered object. Therefore you need to wether destructure your object or access the price directly.

answered Mar 5, 2021 at 14:33

FloWy

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