Print numbers in a string in specific format using python

Question

I was to be able to create a file using python which has data in the specific format shown below. It starts from 00000# where # is 1 and goes all the way to 100000. The same number is present in each line before and after the text My Team.

#output file
000001 My Team 000001
000002 My Team 000002
...all the way to
100000 My Team 100000

I am not sure on how to do this format creation in python. I know it is something simple but I am a bit lost on how to proceed. I am very new to python and I would appreciate if anyone can give me some guidance on this.

Thank you to all.

Sayandip Dutta · Accepted Answer · 2021-01-22 18:29:46Z

1

You can try f-strings added in python 3.6:

PADDING = 6

with open('test.txt', 'w') as fh:
    for i in range(1, 100001):
        print(f'{i:0{PADDING}d} My Team {i:0{PADDING}d}', file=fh)

OUTPUT:

000001 My Team 000001
000002 My Team 000002
...
100000 My Team 100000

Another method would be to use str.zfill (zfill stands from zero-fill):

>>> i = 1
>>> f'{str(i).zfill(PADDING)} My Team {str(i).zfill(PADDING)}'
000001 My Team 000001

edited Jan 22, 2021 at 18:29

answered Jan 22, 2021 at 17:56

Sayandip Dutta

15.9k4 gold badges27 silver badges57 bronze badges

Sign up to request clarification or add additional context in comments.

12 Comments

DeepSpace Over a year ago

Just use str.zfill

Sayandip Dutta Over a year ago

@DeepSpace isn't it slower than f-strings? Nonetheless, I prefer f-string because it gives me more flexibility.

DeepSpace Over a year ago

I don't know, but even if it is, it is going to be in a very small margin, and f'{str(i).zfill(padding)} My Team {str(i).zfill(padding)}' is much more readable. Of course, if you save str(i).zfill(padding) as a variable the speed difference (if it even exists) will be smaller

DeepSpace Over a year ago

@Anna Make sure you are using Python >= 3.6

DeepSpace Over a year ago

I just did some timings, and even f'{str(i).zfill(PADDING)} My Team {str(i).zfill(PADDING)}' (without caching str(i).zfill(PADDING)) is faster

|

Ian Chu · Accepted Answer · 2021-01-22 17:52:31Z

1

If you're looking to make sure that a number always has six digits, you can do that with something like this

def leadingZeros(num, length):
    out_str = str(num);
    while len(out_str) < length:
        out_str = "0" + out_str;
    return out_str;

answered Jan 22, 2021 at 17:52

Ian Chu

3,14311 silver badges16 bronze badges

1 Comment

DeepSpace Over a year ago

Please, drop the semicolons. Also, this is exactly why we have str.zfill

Epsi95 · Accepted Answer · 2021-01-22 17:58:48Z

1

You can use string formatting to achieve this

output_string = ''.join([f'{i:06d} My Team {i:06d}\n'for i in range(1, 100001)])

Alternatively using zfill

output_string = ''.join([f'{str(i).zfill(6)} My Team {str(i).zfill(6)}\n'for i in range(1, 100001)])

edited Jan 22, 2021 at 17:58

answered Jan 22, 2021 at 17:56

Epsi95

9,1071 gold badge19 silver badges37 bronze badges

2 Comments

DeepSpace Over a year ago

Just use str.zfill

Epsi95 Over a year ago

Why, does zfil has advantages?

enterentropy · Accepted Answer · 2021-01-22 18:14:11Z

0

If you want to print the contents of the file which are already in that format then

with open('file.txt','r') as f:
      file_data=f.read()
      l=file_data.split("\n")
      print(*l)

If you want create a file like that then you can use, place the file the same directory as you code is in

with open('test.txt','w') as myfile:
for i in range(1,100001):
    print("{:0>6d} My team {:0>6d}".format(i,i),file=myfile)

answered Jan 22, 2021 at 18:14

enterentropy

12 bronze badges

Collectives™ on Stack Overflow

Print numbers in a string in specific format using python

4 Answers 4

12 Comments

1 Comment

2 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

12 Comments

1 Comment

2 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related