Check if array items are found as certain property value within array of objects [closed]

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I have two arrays and I want to find matching elements of these arrays

const array1 = [{"id": 0, "value": 1}, {"id": 1, "value": 2}, {"id": 2, "value": 3}, {"id": 3, "value": 4}, {"id": 4, "value": 5}, {"id": 5, "value": 6}, {"id": 6, "value": 7}, {"id": 7, "value": 8}, {"id": 8, "value": 9}, {"id": 9, "value": 10}]

const array2 = [0, 1, 11, 12]

how can I find matching elements of array1 and array2?

my expected output is

const array3 = [0, 1]

There will be no matching elements since array1 contains objects, and array2 contains strings. — Or Assayag
– Or Assayag, Commented Jan 18, 2021 at 9:52
Does this answer your question? Check if an array contains any element of another array in JavaScript — emerson.marini
– emerson.marini, Commented Jan 18, 2021 at 9:52
@Shivam In the future, when asking a question, you should provide your inputs (which you have), your expected output (missing), and most importantly, the code you have tried so far to accomplish your goal + links to other posts that didn't work for you (also missing). If you edit your question to include these, some of the dvs might get removed — Nick Parsons
– Nick Parsons, Commented Jan 18, 2021 at 10:03
I'm fairly your question is a dupe of this though: How to find array in array — Nick Parsons
– Nick Parsons, Commented Jan 18, 2021 at 10:07

Yevhen Horbunkov · Accepted Answer · 2021-01-18 10:24:16Z

3

You should make use of Array.prototype.filter() together with Array.prototype.some():

const array1 = [{"id": 0, "value": 1}, {"id": 1, "value": 2}, {"id": 2, "value": 3}, {"id": 3, "value": 4}, {"id": 4, "value": 5}, {"id": 5, "value": 6}, {"id": 6, "value": 7}, {"id": 7, "value": 8}, {"id": 8, "value": 9}, {"id": 9, "value": 10}],
      array2 = [0, 1],
      
      
      result = array2.filter(_id => array1.some(({id}) => id === _id))
      
console.log(result)

edited Jan 18, 2021 at 10:24

answered Jan 18, 2021 at 10:21

Yevhen Horbunkov

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Sanoodia · Accepted Answer · 2021-01-18 09:58:24Z

2

By mapping you can find your array like this

let array2 = ['0', '1']
let found = false;  
array1.map(ele =>{
   let found = (ele.id.toString() === array2[0].toString() && 
                ele.value.toString() === array2[1].toString())? true : false;
})
console.log(found)

answered Jan 18, 2021 at 9:58

Sanoodia

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Manikant Gautam · Accepted Answer · 2021-01-18 10:29:42Z

2

if i understood corretly here is how you can filter your array1 if you want to filter on value use value.toString()

function myFn() {
  let array1 = [{"id": 0, "value": 1}, {"id": 1, "value": 2}, {"id": 2, "value": 3}, {"id": 3, "value": 4}, {"id": 4, "value": 5}, {"id": 5, "value": 6}, {"id": 6, "value": 7}, {"id": 7, "value": 8}, {"id": 8, "value": 9}, {"id": 9, "value": 10}]
  let array2 = ['0', '1','11','12']

  let idArray = array1.map(a => (a.id));
  let filteredArray=idArray.filter(value=>array2.includes(value.toString()));
  console.log(filteredArray);
  
}

myFn();

edited Jan 18, 2021 at 10:29

answered Jan 18, 2021 at 10:02

Manikant Gautam

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4 Comments

Shivam Over a year ago

I am expecting my result array as [0,1].

Manikant Gautam Over a year ago

array2 is already [0, 1] then what would be the relation with array1

Shivam Over a year ago

if my array2 is [0, 1, 11, 12] then?

Manikant Gautam Over a year ago

@Shivam see the edited answer

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