I have an array of objects:
[
{ key : 'a', value1 : 'a1', value2 : 'a2' },
{ key : 'b', value1 : 'b1', value2 : 'b2' }
];
How do I convert it into the following ?
It would be great to achieve this with lodash.
{
a: { value1: 'a1', value2 : 'a2' }
b: { value1: 'b1', value2 : 'b2' }
}
You can use the Array.reduce function:
const res = arr.reduce((acc, o) => {
const {key, ...newO} = o;
return {...acc, [o.key]: newO};
},
{},
);
You could destructure the object and map new objects. Finally assign the spreaded objects to a single object.
const
array = [{ key : 'a', value1 : 'a1', value2 : 'a2' }, { key : 'b', value1 : 'b1', value2 : 'b2' }],
result = Object.assign({}, ...array.map(({ key, ...o }) => ({ [key]: o })));
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }Map the array of objects to an array of [key, rest], where the rest is the original object without the key, and convert to an object using Object.fromEntries(), or lodash's _.fromPairs().
const array = [{ key : 'a', value1 : 'a1', value2 : 'a2' }, { key : 'b', value1 : 'b1', value2 : 'b2' }]
const result = Object.fromEntries(array.map(({ key, ...rest }) => [key, rest]));
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }You can achieve it by LODASH
const res = _.chain(array).keyBy('key').mapValues( v => _.omit(v, 'key')).value()
const result = _.map(res, (v, key) => ({ key, ...v })) You can return to the original array by doing the above code oneSomething like this would work:
const output = {};
[
{ key : 'a', value1 : 'a1', value2 : 'a2' },
{ key : 'b', value1 : 'b1', value2 : 'b2' }
].forEach(row => output[row.key] = { value1: row.value1, value2: row.value2 });
