Loop Script for Nested Arrays - JS

Question

I'm trying to create a loop script for my app that checks if the array of users is full and if not, it puts in the user ID.

My JSON file is based on MongoDB and it has 24 entries (hours). Each entry has a mins array (see below)

I tried the following script, but it's supposed to check each array in a raw disregarding the min value.

const hour = await db.Timer.findOne({hour: time[1]}) // finding an hour in the DB
const timer = await db.Timer.findOne({hour: time[1]}, { mins: {"$elemMatch": {min: time[2]}}}) // finding a minute
let maxUsers = 3
for(let i = 0; i < hour.mins[i].users.length; i++) {
    if(hour.mins[i].users.length < maxUsers){
      console.log(i)
    } 
}

hour and timer are arrays can be found by time[1] (hour) and time[2] (minute). This is what I should work with.

// how the 'mins' array looks like
[
  {
    users: [ 432143, 543254, 6545423 ],
    min: 21
  },
  {
    users: [ 3421, 432143, 43213 ],
    min: 22
  },
  { users: [ 7735 ], min: 23 },
  { users: [], min: 20 }
]

// output for 'hour'
{
  hour: 15,
  mins: [
    { users: [Array], min: 21 },
    { users: [Array], min: 22 },
    { users: [Array], min: 23 },
    { users: [], min: 20 }
  ]
}

// output for 'timer'
{
  mins: [ { users: [Array], min: 21 } ]
}

Please suggest how to check the arrays by minute.

JSON is a textual notation for data exchange. (More here.) If you're dealing with JavaScript source code, and not dealing with a string, you're not dealing with JSON. — T.J. Crowder
– T.J. Crowder, Commented Sep 16, 2020 at 14:02
@T.J.Crowder thanks. I'm a newbie, so maybe I'm wrong here. Could you please help me here? I'd be grateful! — Paul
– Paul, Commented Sep 16, 2020 at 14:11
I'm afraid I don't use MongoDB. Also, I don't think it's clear from the above what the structure of hour and timer is...? — T.J. Crowder
– T.J. Crowder, Commented Sep 16, 2020 at 14:14
@T.J.Crowder, I updated the post, please check it Thank you anyway! — Paul
– Paul, Commented Sep 16, 2020 at 14:30

Paul · Accepted Answer · 2020-09-17 10:49:46Z

1

For those who're interested in the solution.

Here is how I solved my problem:

let mitunes = hour.mins
      const guys = mitunes.filter(mitunes => mitunes.users.length < 3 && mitunes.min > time[2]);
      console.log(guys[0].min)

answered Sep 17, 2020 at 10:49

Paul

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