Click CSS Element with Selenium and python

Question

I am trying to click a button using Selenium.

Below is the code

<button class="_11f5fc88e3dec7bfec55f7f49d581d78-scss _238c8d0c29802f43d5fb66614d042cfa-scss" title="Play" aria-label="Play" data-testid="play-button" style xpath="1">

I tried to do this by the css selector:

searchButton = browser.find_elements_by_css_selector('[class="_11f5fc88e3dec7bfec55f7f49d581d78-scss _238c8d0c29802f43d5fb66614d042cfa-scss"]').click()

MY ERROR: AttributeError: 'list' object has no attribute 'click'

Am I approaching this wrong? Im not understanding the error.

That is not a valid CSS selector. To get the CSS selector, right-click on the mouse on the element(<button class) and click copy > copy selector — Pavan Suvarna
– Pavan Suvarna, Commented Aug 23, 2020 at 6:55
@CarMan does the below answer has solved your issue? if yes, feel free to accept the correct answer with click √ icon. — frianH
– frianH, Commented Aug 24, 2020 at 19:32

bot8080 · Accepted Answer · 2020-08-23 07:12:24Z

0

Refer this link of how to use different selectors..
https://selenium-python.readthedocs.io/locating-elements.html

It is recommended to Copy css selector path by inspecting particular element on website then mouse right click -> copy -> copy css path

or by analyzing the code manually enter path

Here p is paragraph tag and class name is content

element = driver.find_element_by_css_selector('p.content')

answered Aug 23, 2020 at 7:12

bot8080

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frianH · Accepted Answer · 2020-08-23 08:58:44Z

0

AttributeError: 'list' object has no attribute 'click'

This error appear because you use .find_elements, it will return a list.

To solve this issue, try this approach:

Using .find_element, without s.
Or still using .find_elements but with index, like this:

browser.find_elements_by_css_selector('[class="_11f5fc88e3dec7bfec55f7f49d581d78-scss _238c8d0c29802f43d5fb66614d042cfa-scss"]')[0].click()

answered Aug 23, 2020 at 8:58

frianH

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