How to find object in array of objects?

Question

Here is my code in Node:

The results will always be "No" even if the objects are the same object. i tried with "==" and same answer - "no"

  const recipe = await getRecipes(req.params.id); \\ID
  let user = await User.findById(req.user._id); \\ user
  user.recipes.forEach((item) => {

    console.log(item._id); \\ 5f196683308447452cd2c018
    console.log(recipe._id); \\ 5f196683308447452cd2c018
    
    if (item._id === recipe._id) {
      console.log("yes");
    } else {
      console.log("no");
    }
  });
});  ```

You would get a lot of "no" and at most one "yes". Are you sure you're not overlooking it? — VLAZ
– VLAZ, Commented Jul 28, 2020 at 10:24
You are looping through many recipes. At most one of them will have the same ID as recipe._id - that one would print "yes" in the console. Everything else would print "no". Are you sure you're not just missing the "yes"? — VLAZ
– VLAZ, Commented Jul 28, 2020 at 10:29

jsubroto · Accepted Answer · 2020-07-28 10:25:49Z

1

It keeps outputting 'no' because you are comparing 2 different Mongo ObjectId objects.

For example, console.log({a:1} === {a:1}) is false since they are 2 different objects.

If you really wanted to check by the ObjectId, you could do:

item._id.toString() === recipe._id.toString()

answered Jul 28, 2020 at 10:25

jsubroto

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5 Comments

jsubroto Over a year ago

Glad to have helped! :)

Hansaka Sandaruwan Over a year ago

other than using forEach you should consider using findIndex method.

Dnailsa Over a year ago

can you give me example for that?

jsubroto Over a year ago

findIndex() or find() just optimizes the search a bit since it simply returns the first element that it finds instead of going through each element in the array by using forEach()

Dnailsa Over a year ago

how do i use the findIndex instead of foreach?

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