How to sort Array of string in specific string index

Question

So.. Actually, I have a list that has multiple strings on it. And here I want to sort it in specific strings index :

lists = ['AELIA4560005253120', 'KIFLA5000005760000']

Soo.. inside of the lists, there are names (which has caps word in it), code (3 number digits after the name), and secret number (10 digits of code after the previous code).. my question is, can I sort this list by specific strings index which I want to sort it by code (3 number digits after the name)??

# expecting lists after sort
lists_sort = ['KIFLA5000005760000','AELIA4560005253120']

So my expected result is, KIFLA came first and AELIA is second is because KIFLA's codes are 500 and AELIA's codes are 456

Can anyone help me? thank you 😁

Nope.. only the secret codes have the same length which is 10 digit of last codes. — Rizky A Fauzan
– Rizky A Fauzan, Commented Jun 13, 2020 at 5:45
So then the answer you accepted will break if the names are not exactly five letters long. — Mark
– Mark, Commented Jun 13, 2020 at 5:47
Yea, But thanks to the answer, I can improvise the code by changing the index by reverse the index itself which the codes become like this.. res = sorted(lists, key=lambda x: int(x[-13:-10]), reverse = True) — Rizky A Fauzan
– Rizky A Fauzan, Commented Jun 13, 2020 at 5:53

deadshot · Accepted Answer · 2020-06-13 05:32:44Z

2

Try this:

lists = ['AELIA4560005253120', 'KIFLA5000005760000']

res = sorted(lists, key=lambda x: int(x[5:8]) , reverse = True)
#['KIFLA5000005760000', 'AELIA4560005253120']

edited Jun 13, 2020 at 5:32

answered Jun 13, 2020 at 5:28

deadshot

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1 Comment

DarrylG Over a year ago

You probably want int(x[5:8]) in the lambda function.

Tibebes. M · Accepted Answer · 2020-06-13 05:50:59Z

1

Assuming the name is of a variable length, you can use this:

import re

lists = ['AELIA4560005253120', 'KIFLA5000005760000']

lists_sort = sorted(lists, key = lambda x: int(re.search(r'\d{3}', x).group(0)), reverse = True)
print(lists_sort)

edited Jun 13, 2020 at 5:50

answered Jun 13, 2020 at 5:41

Tibebes. M

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2 Comments

Mark Over a year ago

I wonder if int(re.search(r'\d{3}', s).group(0)) would be easier?

Tibebes. M Over a year ago

yeah, thanks for the suggestion. I've updated the answer

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