PHP - json_encode

Question

I generate json files manually this way:

$output_json = '{
"tabela1": {
    "ilosc_wpisow": ';
    $output_json = $output_json.'"'."$ile_wierszy_1".'",'.'
    "tabela": [';


    for ($i = 1; $i <= $ile_wierszy_1; $i++) {
    $g = $i-1;
    $szukana_wartosc_array2[$g] = str_replace(" ",'\n',$szukana_wartosc_array[$g]); 
    $output_json = $output_json.'
    {
    "bajty_przed": '.'"'.$bajty_przed_array[$g].'",
    ';
    $output_json = $output_json.'"szukana_wartosc": '.'"'.$szukana_wartosc_array2[$g].'",
    ';
    $output_json = $output_json.'"bajty_po": '.'"'.$bajty_po_array[$g].'",
    ';
    $output_json = $output_json.'"nowa_wartosc": '.'"'.$nowa_wartosc_array[$g].'"
    }';
    if ($i!=$ile_wierszy_1) { $output_json = $output_json.','; }
    }
    $output_json = $output_json.'
    ]
},';


        $output_json = $output_json.'
"tabela2": {
    "ilosc_wpisow": ';
    $output_json = $output_json.'"'."$ile_wierszy_2".'",'.'
    "tabela": [';

    for ($i = 1; $i <= $ile_wierszy_2; $i++) {
    $g = $i-1;

        $output_json = $output_json.'
    {
    "szukana_wartosc2": '.'"'.$szukana_wartosc2_array[$g].'",
    ';
    $output_json = $output_json.'"zamien_na": '.'"'.$zamien_na_array[$g].'",
    ';
    $output_json = $output_json.'"przesuniecie": '.'"'.$przesuniecie_array[$g].'"
    }';
    if ($i!=$ile_wierszy_2) { $output_json = $output_json.','; }
    }
    $output_json = $output_json.'
    ]
}
}';

Someone help me create the function json_encode? I tried in different ways to add variables to the array, but every time I have something different on the output.

Output: https://pastebin.com/f8keXaY7

Show how you're creating an array. If you need help, you can take a valid json that you've built and use json_decode on it to see how to build it. — aynber
– aynber, Commented May 5, 2020 at 17:28
I'm not sure that I understand the goal. You would like to create a function, which works in the same way as the json_encode? Or you just want to create a simple json? — Random Dude
– Random Dude, Commented May 5, 2020 at 17:35
Your approach is completely wrong. You have 2 inbuilt functions in PHP json_encode and json_decode. Please post the question and expected result clearly, so that we can help you. — Harish ST
– Harish ST, Commented May 5, 2020 at 17:36
https://www.php.net/manual/en/function.json-encode.php There are several examples in this documentation. Take sometime to understand and apply. — Harish ST
– Harish ST, Commented May 5, 2020 at 17:37
you can just create php standart class object and serialize it in the end — Giga Kokaia
– Giga Kokaia, Commented May 5, 2020 at 17:39

Mathieu Vedie · Accepted Answer · 2020-05-05 18:11:19Z

First Step : Build your json structure in a php array and store it in a variable.

Something like that.

$json_source = [
    'tabela1' => [
        "ilosc_wpisow" => $ile_wierszy_1,
        "tabela"       => array_map(function($key) use ($szukana_wartosc_array, $bajty_przed_array, $bajty_po_array, $nowa_wartosc_array) {
            return [
                "bajty_przed"     => $bajty_przed_array[$key],
                "szukana_wartosc" => str_replace(" ", '\n', $szukana_wartosc_array[$key]),
                "bajty_po"        => $bajty_po_array[$key],
                "nowa_wartosc"    => $nowa_wartosc_array[$key],
            ];
        }, array_keys($szukana_wartosc_array)),

    ],
    'tabela2' => [
        'ilosc_wpisow' => $ile_wierszy_2,
        'tabela'       => array_map(function($key) use ($szukana_wartosc2_array, $zamien_na_array, $przesuniecie_array) {
            return [
                'szukana_wartosc2' => $szukana_wartosc2_array[$key],
                "zamien_na"        => $zamien_na_array[$key],
                "przesuniecie"     => $przesuniecie_array[$key],
            ];
        }, array_keys($szukana_wartosc2_array)),
    ],
];

Second Step : Use json_encode function.

echo json_encode($json_source);

And, If your output is always different, it means that your input is always different.

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