code coverage of a file using coverage.py using a python script

Question

I want to get the code coverage of a python file say "Test.py". Now, when I write the script for this using coverage.py, it looks like this,

import coverage

cov = coverage.Coverage()
cov.start()

#pass the data

cov.stop()
cov.save()
cov.html_report()

now in place of pass the data, I want to pass Test.py, How can I do this?

Freddy · Accepted Answer · 2021-01-25 06:59:21Z

2

I just have the same doubt.

This gave me the result you want using pytest

import coverage
import pytest

cov = coverage.Coverage()
cov.start()

pytest.main(['-x', 'api/tests.py', '-vv'])

cov.stop()
cov.report()

answered Jan 25, 2021 at 6:59

Freddy

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Comments

Ned Batchelder · Accepted Answer · 2020-04-13 19:03:13Z

0

You don't need to use the coverage API. Just run your program with coverage:

$ coverage run Test.py

answered Apr 13, 2020 at 19:03

Ned Batchelder

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