Calling a function within a function in a loop - python

Question

I didn't find a solution in "similar" questions. I like to call a function in a function in a loop. the solution will not be to set "parameters" in front of the function (def inner) I try to call. I like to call the "def inner" in the end of the loop. Thanks!

    def meta1():
        def inner():
            print("hello inner2")
            parameters = {"Name": "XYZ","max_time": 35}
            return parameters

    def meta2():
        def inner():
            print("hello inner2")
            parameters = {"Name": "XXX","max_time": 25}
            return parameters

the loop over the functions

    for func in [meta1, meta2]:
        x = func()
        print(x['Name'])

        print("here is some other code between. The solution is not to change the functions!")


        print(func(inner())) #here i need some help, thanks

The question doesn't look clear. I don't see a body for the inner functions defined — Asnim P Ansari
– Asnim P Ansari, Commented Nov 28, 2019 at 20:30
Your formatting is broken ... is the body of inner() only the print? — Tim Richardson
– Tim Richardson, Commented Nov 28, 2019 at 20:32
please be more clear in what you want to achieve... and check indentation as your inner function now has no code in it — Chrisvdberge
– Chrisvdberge, Commented Nov 28, 2019 at 20:32
sorry to be not clear. may mixed some things. i will try to explain what i achieve. @tim - no i will be a calculation. — Alex
– Alex, Commented Nov 28, 2019 at 20:33
The python you have used is a synax error. After def inner(), you must have indenting. — Tim Richardson
– Tim Richardson, Commented Nov 28, 2019 at 20:35

wwii · Accepted Answer · 2019-11-28 21:01:57Z

1

Not clear why you want/need to do this but if each meta also returns its inner function then it is easy.

def meta1():
    def printer():
        print("hello xyz")
    parameters = {"Name": "XYZ","max_time": 35}
    return parameters,printer

def meta2():
    def printer():
        print("hello xxx")
    parameters = {"Name": "XXX","max_time": 25}
    return parameters,printer

for func in [meta1, meta2]:
    x,inner = func()
    print(x['Name'])
    print("here is some other code between. The solution is not to change the functions!")
    print(inner())

answered Nov 28, 2019 at 21:01

wwii

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Comments

Tim Richardson · Accepted Answer · 2019-11-28 21:05:25Z

While it is not clear what you want to do, this code may help You can copy and paste it into an Idle window, and run it.

The point of my answer is to introduce you to classes, which in Python may be the best fit for the level of abstraction you want. Classes are a major feature of Python, and when you learn about them you will also discover static members and so on. But for now ...

def meta1():
    def inner():
        print("hello inner2")
        parameters = {"Name": "XYZ","max_time": 35}
        return parameters


class Meta1ClassExample:
    def inner(self):
        print("hello inner2")
        parameters = {"Name": "XYZ","max_time": 35}
        return parameters




if __name__ == '__main__':
    try:
        meta1.inner()  #AttributeError: 'function' object has no attribute 'inner'
    except AttributeError:
        print("As expected, looking for the inner function is an error")

    metaclass = Meta1ClassExample()
    p = metaclass.inner()
    print (p)

ctenar · Accepted Answer · 2019-11-28 21:11:14Z

If your goal is to use the inner functions outside meta1 and meta2, respectively, you can try something like this:

def meta1():
    def printer():
        print("hello xyz")
    parameters = {"Name": "XYZ","max_time": 35}
    return printer, parameters

def meta2():
    def printer():
        print("hello xxx")
    parameters = {"Name": "XXX","max_time": 25}
    return printer, parameters

for func in [meta1, meta2]:
    printer_fct, x = func()
    print(x['Name'])

    print("here is some other code between. The solution is not to change the functions!")


    print(printer_fct()) #here i need some help, thanks

Edit: In the last line, you would probably want a simple call to the function printer_fct(), since the application of print only outputs None because printer_fct() does not return anything.

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