Take input from user and execute the python script at the same time

Question

i have a python script name as neural_net.py . It classify the mnist dataset. What i want to do is to run it via command line by taking input from user. The following snippet is taking input from user

file=input()
from PIL import Image
im = Image.open(file).convert('L')
imr=np.array(im).T
single_test = imr.reshape(1,400)
plt.figure(figsize=(5,5))
plt.imshow(imr)
print("value is",nn.predict(single_test))

in command prompt i have to run it as following

python neural_net.py

execute the above line and then give the input

pic_0.png

and it return me the output. What i want is to do the both of above things as a single command such as

python neural_net.py pic_0.png

use file = sys.argv[1] to get it. If you run with more arguments then you have sys.argv[2], etc. If you need more complex soluton like script.py --input pic_0.png --output image.png then see module argparse — furas
– furas, Commented Apr 28, 2019 at 1:11

furas · Accepted Answer · 2019-04-28 01:21:48Z

8

Use in code

import sys

file = sys.argv[1]

to get it.

Now you can run it as

python neural_net.py pic_0.png

and file will be pic_0.png

If you run with more arguments

python neural_net.py pic_0.png pic_1.png pic_2.png

then you will have sys.argv[2], sys.argv[3], etc. with values pic_1.png, pic_2.png

If you need more complex soluton like

script.py --input pic_0.png --output image.png

then see module argparse

import argparse

parser = argparse.ArgumentParser()
parser.add_argument('-i', '--input')
parser.add_argument('-o', '--output', default='output.png')
args = parser.parse_args()

file = args.input
output_file = args.output

edited Apr 28, 2019 at 1:21

answered Apr 28, 2019 at 1:16

furas

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Comments

silverton · Accepted Answer · 2019-04-28 01:31:41Z

1

EDIT: I think I realized why you are unhappy. You need to provide a path in addition to the file name, you can either do this with args like

python run.py "c:/users/user/desktop/pictures/pngs/file.png"

and use the original answers. Or simply just put a general path in the code and use the arg for the specific file.

IMAGE_FOLDER = "c:/users/user/desktop/pictures/pngs/"
file = IMAGE_FOLDER + sys.argv[1]

Original:

This is pretty much straight from google results:

CML:

    python neural_net.py pic_0.png

Code:

     import sys
     print sys.argv[1]

Result:

    "pic_0.png"

Many thanks for Google and https://www.pythonforbeginners.com/system/python-sys-argv

edited Apr 28, 2019 at 1:31

answered Apr 28, 2019 at 1:15

silverton

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2 Comments

silverton Over a year ago

I'm not sure I understand the question, given this post and @furas, who also answered as I would've expected is also downvoted.

furas Over a year ago

maybe someone understand question in different way and he downvoted answers. I think your answer is correct for this question.

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