How can I use regex in Python to extract the string?

Question

I have to extract a string from a network response which looks like shown below:

Hello, did you get this message?
I want to check it,
let me know!

Here is your encrypted text:
96a1e3424f4cfa23db131173d7f8c93396a1e3424f4cfa23db131173d7f8c933182bc4e99a47abb5deaa51741527dd2b478746563aecc40d5d6f6597370338a7

Some more text:

The response contains "\r\n" or if checked on Linux, then "\n"

How can I extract the hash from above message?

I wrote something like below but it did not extract the hash:

import re

# data corresponds to network response which contains the \r\n characters

matchObj = re.match( r'(.*?)your encrypted text:\r\n(.*)\r\n.*', data)

if matchObj:
    print matchObj.group(2)

Thanks.

Your regex does not fit your text at all.

Klaus D.
– Klaus D.

2018-11-25 04:49:23 +00:00
Commented Nov 25, 2018 at 4:49 — Klaus D.
– Klaus D., Commented Nov 25, 2018 at 4:49
Where is your encrypted text: in your input?

anubhava
– anubhava

2018-11-25 05:01:16 +00:00
Commented Nov 25, 2018 at 5:01 — anubhava
– anubhava, Commented Nov 25, 2018 at 5:01
I updated it now. That string is in the input itself.

Neon Flash
– Neon Flash

2018-11-27 02:40:20 +00:00
Commented Nov 27, 2018 at 2:40 — Neon Flash
– Neon Flash, Commented Nov 27, 2018 at 2:40

John Zwinck · Accepted Answer · 2018-11-25 04:52:07Z

1

Read the input one line at a time (using readlines() or split('\n')) and do this:

for line in lines:
    match = re.match('^([0-9a-f]+)$', line)
    if match:
        print(match.groups(1)[0])

answered Nov 25, 2018 at 4:52

John Zwinck

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Comments

user7121223 · Accepted Answer · 2018-11-25 10:30:28Z

1

If it's okay that you don't use regex, try it:

lines = open(file_name, 'r').read().splitlines()

for i, line in enumerate(lines):
    if line.strip() == "your encrypted text:":
        my_text = lines[i + 1]
        break

answered Nov 25, 2018 at 10:30

user7121223

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