Return object with highest number from array containing multiple objects

Question

I was able to figure out how to return the highest number from a associative array with multiple objects. But I need the whole object.

I prepared this example:

var data = [
     { nr: 235, text: "foo" }
    ,{ nr: 351, text: "bar" }
];

var highestNr = Math.max.apply(null, Object.keys(data).map(function(e) {
             return data[e]['nr'];
         }));
                
var index = "???";

console.log("Highest 'nr': " + highestNr);
console.log("Index at nr "+ highestNr + ": " + index);

//console.log(data[index]);

I need the index or the whole object. I need to show the text from the object with the highest number.

technical point, you haven't got an associative array here. You've got an array containing two objects. JS doesn't have associative arrays, it has objects - although it is possible to use them in a similar way to you might use an associative array in, say, PHP, e.g. by looping through the properties of the object. — ADyson
– ADyson, Commented Nov 13, 2018 at 12:58
Once you have the highest number can't you just filter the array on that value? — StudioTime
– StudioTime, Commented Nov 13, 2018 at 12:59
@DarrenSweeney: you could, but see the answer from NinaScholz for a better technique. — Scott Sauyet
– Scott Sauyet, Commented Nov 13, 2018 at 13:00
@ADyson, thanks for the hint. I changed the title of the question. — Black
– Black, Commented Nov 13, 2018 at 14:09

Nina Scholz · Accepted Answer · 2018-11-13 13:01:49Z

7

You could reduce the array by selecting the one with a greater value.

var data = [{ nr: 235, text: "foo" }, { nr: 351, text: "bar" }], 
    topNr = data.reduce((a, b) => a.nr > b.nr ? a : b);

console.log(topNr);

edited Nov 13, 2018 at 13:01

answered Nov 13, 2018 at 12:59

Nina Scholz

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Comments

Nitish Narang · Accepted Answer · 2018-11-13 13:10:07Z

3

You can "sort" the array by "nr" property in descending order and get first element "[0]"

var data = [
     { nr: 235, text: "foo" }
    ,{ nr: 351, text: "bar" }
];

// slice added so that original data is not mutated
var result = data.slice(0).sort((a,b) => b.nr - a.nr)[0]

console.log(result)

edited Nov 13, 2018 at 13:10

answered Nov 13, 2018 at 12:58

Nitish Narang

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3 Comments

Keith Over a year ago

Using sort is a good idea, especially if you also wanted the nth highest etc. But it might be worth pointing out this will mutate the array, so you might want to do [].concat(data).sort( if this is not desired.

Scott Sauyet Over a year ago

Sorting is fine for small lists. But it's going to be O(n log n), whereas this can be done in O(n) as the reduce answers show.

Nitish Narang Over a year ago

@ScottSauyet Thanks for pointing complexity. Correct, it depends upon the size of array.

Roland Ruul · Accepted Answer · 2018-11-13 13:03:36Z

1

You can also use findIndex() method:

var data = [
     { nr: 235, text: "foo" }
    ,{ nr: 351, text: "bar" }
];

var highestNr = Math.max.apply(null, Object.keys(data).map(function(e) {
    return data[e]['nr'];
}));
                
var index = data.findIndex(function(ln) {
    return ln.nr === highestNr;
});

console.log("Highest 'nr': " + highestNr);
console.log("Index at nr "+ highestNr + ": " + index);

//console.log(data[index]);

answered Nov 13, 2018 at 13:03

Roland Ruul

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