Powershell how to process a variable array

Question

I have the following situation in powershell:

$arrayX = 0..1
$arrayY = 0..10

$array1 = @()
$array2 = @()
for ($i = 0; $i -lt $arrayY.Length; $i++){  
        $array1 += $arrayX[0] + $arrayY[$i]
        $array2 += $arrayX[1] + $arrayY[$i]
}

Both $arrayX and $arrayY can be variable in length. If i extend $arrayX by 1 i'll need to adjust the code to take the third value into account. like this:

$arrayX = 0..2
$arrayY = 0..10

$array1 = @()
$array2 = @()
$array3 = @()
for ($i = 0; $i -lt $arrayY.Length; $i++){  
        $array1 += $arrayX[0] + $arrayY[$i]
        $array2 += $arrayX[1] + $arrayY[$i]
        $array3 += $arrayX[2] + $arrayY[$i]
}

What is the best practice in a situation like this to have this work automatic?

Why two arrays? Are you really looking for an associative array (hashtable)? — Bill_Stewart
– Bill_Stewart, Commented Oct 1, 2018 at 21:10
this is a simplified version of the problem to make it understandable. i have a complicated math equation that comes down to this. — secondplace
– secondplace, Commented Oct 1, 2018 at 21:14
Why are you using powershell to solve math problems @secondplace? — Maximilian Burszley
– Maximilian Burszley, Commented Oct 1, 2018 at 22:01

n0rd · Accepted Answer · 2018-10-01 22:36:59Z

2

First, please consider not using the += operation with arrays: it will hurt performance a lot on larger arrays. Since you know the array size in advance you can allocate all required memory in advance:

$array1 = New-Object object[] $arrayY.Length

(you may want to use more specific type instead of object: int or float/double will work)

Next, instead of assigning each array to a variable, you can instead create array of arrays:

$arrayX = 0..2
$arrayY = 0..10

$resultArrays = New-Object int[][] $arrayX.Length

for ($x = 0; $x -lt $resultArrays.Length; ++$x)
{
    $resultArrays[$x] = New-Object int[] $arrayY.Length
}

for ($y = 0; $y -lt $arrayY.Length; ++$y)
{
    for ($x = 0; $x -lt $arrayX.Length; ++$x)
    {
        $resultArrays[$x][$y] = $arrayX[$x] + $arrayY[$y];
    }
}

for ($x = 0; $x -lt $resultArrays.Length; ++$x)
{
    Write-Output "array $($x): $($resultArrays[$x] -join ' ')"
}

answered Oct 1, 2018 at 22:36

n0rd

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2 Comments

secondplace Over a year ago

I'll adapt to your advice to not use += if i know the array length. It works like a charm.

n0rd Over a year ago

If you don't know the size in advance, use something that is resize friendly. System.Collections.Generic.List[object] should work much better.

Nas · Accepted Answer · 2018-10-01 22:22:47Z

0

Is this what you are looking for?

$arrayX = 0..2
$arrayY = 0..10

$arrayX | ForEach-Object {
    $aX = $_
    New-Variable -Name ('array' + $($aX+1)) -Value ($arrayY | ForEach-Object {$_ + $aX}) -Force
}

answered Oct 1, 2018 at 22:22

Nas

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