PHP Check Url and detect empty parameters parts

Question

I Have Url structure for multi language system like this:

for default language ie: en

localhost/cms

And Another Language Like:

localhost/cms/fr

localhost/cms/de

localhost/cms/es

Now I have this function for detect empty url language short name parts and set to default language:

function urlss(){

    $uri = $_SERVER['REQUEST_URI'];

    $languages = ['en', 'fr', 'es', 'de'];

    // this is my default language
    $defaultLang = 'en';

    // $currentLang is the language I'll use to show the contents
    $currentLang = $defaultLang;

    $uri = ltrim(rawurldecode($uri), '/');
    $parts = explode('/', $uri);

    if( ! empty($parts) && in_array(strtolower($parts[0]), $languages)) {
        $currentLang = array_shift($parts);
    }

    $routableUri = implode('/', $parts);

return $routableUri;

}

Check in Url: localhost/cms/ and Output Is: cms/ and not work true.

In action I need to check My url, if not detect language short name ie: en default language = en and then put in session or cookie But if detect language short name ie: fr es de set session or cookie to this language.

How do can I fix my problem and check my url for language short name?!

Are you sure you want to write your own routing system? Why not use an existing one that can handle all that parsing stuff for you? — Nico Haase
– Nico Haase, Commented Jun 19, 2018 at 7:36

fubar · Accepted Answer · 2018-06-21 09:21:58Z

1

I would approach this problem using a regular expression.

// Prepare request URI, available languages and default language
$url = $_SERVER['REQUEST_URI'];
$languages = ['en', 'fr', 'es', 'de'];
$default = 'en';

// Build regular expression and attempt to match language in URL
preg_match('/^\/cms\/(' . implode('|', $languages) . ')\//', $url, $match);

// Set language to match or default to English
$language = $match[1] ?? $default;

// Remove default language from URL
$url = preg_replace("/\/{$default}/", '', $url);

edited Jun 21, 2018 at 9:21

answered Jun 19, 2018 at 6:09

fubar

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12 Comments

NewCod3r Over a year ago

all output is en. ie: check localhost/cms/fr output is : en. localhost/cms ouput is: en localhost/cms/de output is 'en' and more .....

fubar Over a year ago

Your example URLs show the language portion being the first part of the request URI - example.com/de, example.com/fr? Please update your question to show representative examples.

NewCod3r Over a year ago

Ok. You Right. I edit My Q. Actually i check in my localhost url and then in real url.

fubar Over a year ago

I've updated my answer based on the URL always starting with /cms/. If this isn't correct, please update your question again.

NewCod3r Over a year ago

thanks worked now. but for route url i need to print full structure like this: for another lang cms/fr/article/slug/... and for default lang cms/article/slug/....

|

jagad89 · Accepted Answer · 2018-06-19 06:29:16Z

The regex approach is better one another way is you can take an intersection of $languages array with URL $parts.

function urlss(){

    $uri = $_SERVER['REQUEST_URI'];

    $languages = ['en', 'fr', 'es', 'de'];

    // this is my default language
    $defaultLang = 'en';

    // $currentLang is the language I'll use to show the contents
    $currentLang = $defaultLang;

    $uri = ltrim(rawurldecode($uri), '/');
    // uri might have many / characters
    $parts = explode('/', $uri);

    if( ! empty($parts)) {
        $result = array_uintersect($languages , $parts, "strcasecmp");
        if(!empty($result)){ 
           $currentLang = $result[0];
           $parts = array_diff($parts, [ $result[0] ]);
        }
    }

    $routableUri = implode('/', $parts);

    return $routableUri;

}

Muhammed Hafil · Accepted Answer · 2018-06-19 06:52:37Z

0

$languages = ['en', 'fr', 'es', 'de'];
$defaultLang = 'en';

$url = $_SERVER['REQUEST_URI'];
$url = rtrim($url, '/');//remove last slash if available
$parsed_arr = parse_url($url);//not necessary if you don't want to validate url 
$segments = explode("/", $parsed_arr['path']);//split parsed url into segments
$language = end($segments); //take the last one

if(in_array($language,$languages))
    $currentLang = $language;
else
    $currentLang = $defaultLang;

edited Jun 19, 2018 at 6:52

answered Jun 19, 2018 at 6:39

Muhammed Hafil

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Comments

Er. Amit Joshi · Accepted Answer · 2018-06-19 08:43:32Z

Lets have a try this code :

Check This out list()

Rest you can easily change as per your need but i have corrected the logic of function

<?php
   $currentUrls= array('cms/es','cms/en','cms/de','cms/fr','cms/');
   echo 'Before::<br >';
   foreach($currentUrls as $currentUrl){
      echo ($currentUrl);
     echo '<hr/>';
   }

function urlss($currentUrl){
    $uri =$currentUrl;
    $languages = ['en', 'fr', 'es', 'de'];
    // this is my default language
   $defaultLang = 'en';
   // $currentLang is the language I'll use to show the contents
   $currentLang = $defaultLang;
   $uri = ltrim(rawurldecode($uri), '/');       
   list($cms,$url_language) = explode('/', $uri);     

  //if langugage is in array then 
  if( in_array( strtolower($url_language), $languages)){
      $currentLang = $url_language;      
  }else { 
      $currentLang = $defaultLang;      
  }

  $newUrl = array($cms,$currentLang);
  $routableUri = implode('/', $newUrl);
  return $routableUri;
 }

 echo '<br ><br >After::<br >';
 foreach($currentUrls as $currentUrl){
    echo urlss($currentUrl);
    echo '<hr/>';
 }

?>

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