Use docker environment path variable in bash script

Question

I am trying to create a docker file to run a machine learning algorithm with parameters given in config.json file. Simplified version of my docker command looks like this

docker run --rm -it \
        -e "CONFIG=work/algorithms/config.json" \
        -e "SRC_TYPE=csv"
        --entrypoint /bin/bash \
        $(DOCKER_REPO)/$(DOCKER_IMAGE):$(DOCKER_VERSION)

Andy bash script running python command looks like this.

#!/bin/sh
python work/algos/neural_network.py \
--ml_conf "$CONFIG" \
--src_type "$SRC_TYPE" \
--log resources/logs/nn_iris.log

When I use the CONFIG variable in the script like this, It does not work. But the SRC_TYPE variable works. Could you please let me know the right way to use environment variables which contain path.

you can use spaces around the =? doc docker I suggest -e "SRC_TYPE=csv" ... — kyodev
– kyodev, Commented Apr 10, 2018 at 2:24
I am not using spaces in my original code. I typed spaces when copy pasting here by mistake. I'll edit it out — emperorspride188
– emperorspride188, Commented Apr 10, 2018 at 5:08

Mathers · Accepted Answer · 2018-04-10 05:29:53Z

1

I think you would like to use the config inside the running docker container. If so you should use docker volumes instead. Please see reference here

for example: docker run -v /work/algorithms/config.json:/path/to/target -it <image_name:tag>

answered Apr 10, 2018 at 5:29

Mathers

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