How to Loop in threaded script on Python

Question

Right now I have code in my script

def run(self):
        while True:
            try:
                self.one()
                self.two()
                self.three()
                self.four()
            except (IndexError, ProxyError, SSLError, ConnectionError, errno.ECONNREFUSED):
                print statusTime(self.index) + 'Bad Proxy'
                break

def jobWorker(username,password,proxy):
    bot = Bot(username,password,proxy)
    bot.start()
    bot.join()
    return

How can I tell python to continuously run def run(self) so basically keep looping through self.one(), self.two(), self.three(), self.four() so it doesnt stop. Right now each Bot stops at self.four() and doesnt start again at self.one()

And there is no exception thrown?

peremeykin
– peremeykin

2018-03-06 21:24:17 +00:00
Commented Mar 6, 2018 at 21:24 — peremeykin
– peremeykin, Commented Mar 6, 2018 at 21:24
no without exception, i just want it to keep running

Sid
– Sid

2018-03-06 21:27:38 +00:00
Commented Mar 6, 2018 at 21:27 — Sid
– Sid, Commented Mar 6, 2018 at 21:27

Andersson · Accepted Answer · 2018-03-06 21:01:00Z

1

you can put the function with in

def __init__(self):  
    self.run()

edited Mar 6, 2018 at 21:01

Andersson

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answered Mar 6, 2018 at 20:58

Ahmad

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2 Comments

Sid Over a year ago

Ive put that at the end of my script however it still finishes after self.four()

Ahmad Over a year ago

you should put it with the same class of the method run(self)

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