I have this URL:
http://www.example.com/get_url.php?ID=100&Link=http://www.test.com/page.php?l=1&m=7
When I print $_GET['Link'], I see only http://www.test.com/page.php?l=1.
Where is &m=7?
3 Answers
If you want to pass an url as a GET parameter, you'll have to URL-encode it.
The problem is, the server sees & as ending the Link parameter. This means you're actually getting:
$_GET['ID'] = '100';
$_GET['Link'] = 'http://www.test.com/page.php?l=1';
$_GET['m'] = '7';
What you want to do is use urlencode. Example:
$link = 'http://sample.com/hello?a=5&b=6&d=7';
$address = 'http://site.com/do_stuff.php?link='.urlencode($link)
External references:
answered Jan 24, 2011 at 9:33
Sebastian Paaske Tørholm
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3 Comments
mingos
Great answer. Let me just quickly add that when you retrieve the value, you'll want to use urldecode():
$link = urldecode($_GET['Link']; :)
Sebastian Paaske Tørholm
Actually you don't need to
urldecode; that's automatically handled for you by PHP.mingos
Is it? That's nice, thanks for correcting me then, I wasn't aware of this one.
It's a separate value. If you pass it this way, the GET values are:
ID=100
Link=http://www.test.com/page.php?l=1
m=7
The & character separates values passed by GET.
In order to pass the entire thing, you need to encode it properly (see Sebastian's answer).
Comments
(see sebastian's answer).The server sees & as the ending parameter so u won't get the values after &.If u want to get the entire thing u need to encode the entire link using "function urlencode()" before passing the parameters
&m=7is part of the "main" URLhttp://www.xxx.com/get_url.php...