I'm trying to pass a variable to a custom Perl script.
$file="my_wa/fin"
if [[ "$file" == *"fin" ]]; then
script.pl
fi
In my script I try to use $file as my path to open and read a file
my $input_filename = "$ENV{file}";
I understand that I need to export it somehow and receive it in my Perl code,
but it doesn't recognize $file. - it works perfectly if I just write my_wa/fin.
You did not export the variable in the shell before calling the perl program.
Paste your shell code into http://www.shellcheck.net/ -- it will tell you your other shell error.
you can pass $file as an argument
$file="my_wa/fin"
if [[ "$file" == *"fin" ]]; then
script.pl \"$file\"
fi
Then access the data
my $input_filename = $ARGV[0];
Yes, you will need to export the environment variable file in your shell before the perl script execution. Also you may want to make sure to include full path to the file.
export file=/full/path/to/my/file/my_wa/fin
Or making use of pwd if it is relative to current working directory:
export file="$(pwd)/my_wa/fin"
