I created this program and I need it to output like this:
How can I do that?
n=int(input(""))
L = []
x=0
c=0
while x<=n-1:
Numero=int(input(""))
final="*"*Numero,Numero
L.append(final)
x=x+1
for elem in L:
print(elem)
-
TypeError: sequence item 1: expected str instance, int found. How to convert from int to str. Thanks for your help!Francisco Perez– Francisco Perez2017-05-22 01:42:12 +00:00Commented May 22, 2017 at 1:42
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3 Answers
elem is a tuple of a string and an integer number. There are several ways to display it as a string:
print(*elem)
print("%s %d" % elem)
print("{} {}".format(*elem))
print(elem[0], elem[1])
2 Comments
Francisco Perez
One final question why i get None in the last line of the output? pastebin.com/f8uwqMe2
DYZ
Because your function does not have a
return and implicitly returns a None.You can use format() to append strings:
n=int(input("Please input number"))
r=["*"*int(input("")) for i in range(n)]
for i in r:
print("{} {}".format(i,len(i)))
Output:
Please input number4
4
2
3
1
**** 4
** 2
*** 3
* 1
Comments
You want to unpack the arguments to the function using *. So your print statement would become:
print(*elem)
See the python tutorial for more information.
>>> e = ('****', 4)
>>>> print(e)
('****', 4)
>>> print(*e)
**** 4
