Json.Net, how to create json dynamically by path?

Question

I'm new to Json.net, so I'm not sure if I'm doing this the right / best way, but I can't figure this out:

I'm creating an output JObject:

JObject joOutput = new JObject();

Now, I have a list of paths to values:

a.b.c = 5
a.b.d = 7
a.c.q = 8

So I want to populate the joOutput object in the obvious way using that hierarchy.

I can't seem to find a way to set the value by path, obviously creating the path along the way if it doesn't exist.

I'm trying to split the path on the .'s and create the nodes, but I can't even get that far as the api is very confusing.

Can you point me in the right direction?

Thanks!

What do you plan on using joObject for that can't be done with a ? — James Curran
– James Curran, Commented May 19, 2017 at 18:01

James Curran · Accepted Answer · 2017-05-19 18:35:30Z

2

string a = @"{""b"": {""c"":5, ""d"":7}, ""c"": {""q"":8}}";
JObject joObject = JObject.Parse(a);

UPDATE:

var B = new JObject();
B.Add("c", 5);
B.Add("d", 7);

var C = new JObject();
C.Add("q", 8);


JObject A = new JObject();
A.Add("b", B);
A.Add("c", C);

UPDATE2, for completeness, here is Vladimir's method:

var B = new Dictionary<string, int> { ["c"] = 5, ["d"] = 7 };
var C = new Dictionary<string, int> { ["q"] = 5, ["8"] = 7 };
var A = new Dictionary<string, object> { ["b"] = B, ["c"] = C };

var AA = JObject.FromObject(A);

edited May 19, 2017 at 18:35

answered May 19, 2017 at 18:10

James Curran

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4 Comments

SledgeHammer Over a year ago

I need to create it DYNAMICALLY, that was just an example set. It might be a.q.z on the next run. I just get a list of paths and I need to create the json from that.

Manfred Radlwimmer Over a year ago

@SledgeHammer you do realize that you can put that string together however you want, right?

SledgeHammer Over a year ago

@ManfredRadlwimmer, the whole point was to use the API instead of creating the string myself.

SledgeHammer Over a year ago

Ah, I see what the issue was... I was using the JObject incorrectly. I was assuming the name was a property of the object and its not. Thanks.

Vladimir Chikrizov · Accepted Answer · 2017-05-19 18:14:02Z

-1

Try to solve your problem by using Dictionary with string key and object value.

Dictionary<string,object> myJsonObj = new Dictionary<string, object>;

Each element inside can be also same dictionary.

answered May 19, 2017 at 18:14

Vladimir Chikrizov

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2 Comments

Vladimir Chikrizov Over a year ago

myJsonObj.Add("subElement", new Dictionary<string, object>); myJsonObj["subElement"].Add("subsubElement", 1);

Vladimir Chikrizov Over a year ago

After serialization it will be {"subElement" : { "subsubElement" : 1 } }

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