Java sorts both integer arrays

Question

I do not understand why arrSort gets sorted too even if I did not declare it to be sorted?

arrSort1 = arrSort does not mean arrSort = arrSort1 right?

public static void main(String[] args) {
    int[] arrSort = {4024, 4209, 9254, 8996, 9017, 6679, 3412, 6546, 2682, 42};
    int[] arrSort1 = arrSort;
    displayArray(arrSort);
    displaySorted(arrSort1);
    displayArray(arrSort);
}
public static void displayArray(int[] arrList){
    for(int i = 0; i < arrList.length; i++)
        System.out.print(arrList[i] + " ");
    System.out.println();
}
public static void displaySorted(int[] arrSort1){
    Arrays.sort(arrSort1);
    for(int i = 0; i < arrSort1.length; i++){
        System.out.print(arrSort1[i] + " ");    
    }
    System.out.println();
}

The output says

4024 4209 9254 8996 9017 6679 3412 6546 2682 42 
42 2682 3412 4024 4209 6546 6679 8996 9017 9254 
42 2682 3412 4024 4209 6546 6679 8996 9017 9254

Ousmane D. · Accepted Answer · 2017-05-13 00:27:14Z

1

Both arrSort1 and arrSort are referencing the same array hence the outcome, you might want to use Arrays.copyOf.

Example:

int[] arrSort1 = Arrays.copyOf(arrSort,arrSort.length);

answered May 13, 2017 at 0:27

Ousmane D.

56.6k8 gold badges101 silver badges134 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

TuyenNTA · Accepted Answer · 2017-05-13 00:30:05Z

0

It's the same with pointer in C++, You are assign arrSort1 = arrSort then they are point to the same place in memory. When you do some thing with one then the other will change too. You may try to new it before assign

answered May 13, 2017 at 0:30

TuyenNTA

1,2141 gold badge12 silver badges21 bronze badges

Collectives™ on Stack Overflow

Java sorts both integer arrays

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related