Accessing JSON encoded MuliDimensional array using jQuery

Question

I have an multidimensional array

$array = array(
    "Level1"=>array(
        "Level11"=>array(
            "level111"=>'value1',
            "level112"=>'value2',
            ),
        "Level12"=>array(
            "level121"=>'value1',
            "level122"=>'value2',
            ),
        ),
    "Level2"=>array(
        "Level21"=>array(
            "level211"=>'value1',
            "level212"=>'value2',
            ),
        "Level22"=>array(
            "level221"=>'value1',
            "level222"=>'value2',
            ),
        )
    );
echo json_encode($array);

This encoded JSON is sent after receiving AJAX POST request using jQuery.

$.post(
    'mypage.php',
    {
        param1: value1,
        param2: value2
    },
    function(data) {
        //Now I can access the 1st level JSON value easily like
        alert(data.Level1); 

        // But

        // I am trying to access the values like 

        alert(data.Level1.Level11.level112); //which is not possible
    },
    "json"
);

If you have understood my question, do you know how I could tackle this problem.

Have you checked what string is generated by json_encode()? Btw even data.level1 should not work, because the key is named Level1 (capital L). — Felix Kling
– Felix Kling, Commented Nov 12, 2010 at 10:48
@Pekka, I dont know, that code was supposed to work, but it didn't. @Felix Kling, Yes it can be accesed as array, like dt = data.level1; i = dt['level11'][level112] and I just created a sample of my code, I will correct it right away, I have 3 more levels in my actual code. — Starx
– Starx, Commented Nov 12, 2010 at 10:51
Works for me: jsfiddle.net/KjHJd (JSON generated by codepad.org/jUiDCeq6), the error must be somewhere else. You should get some error message on the console. — Felix Kling
– Felix Kling, Commented Nov 12, 2010 at 10:57

Felix Kling · Accepted Answer · 2010-11-12 10:51:40Z

1

Ok, my guess: You use capital letters in some of your keys in PHP but not in JS. Your line should be:

data.Level1.Level11.level112

Note that it is Level1 with captial L, not level1.

DEMO

answered Nov 12, 2010 at 10:51

Felix Kling

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4 Comments

Felix Kling Over a year ago

@Starx: Well, then you should provide a better example. As you can see in the demo, this would be what json_encode generates. And it is accessible.

Starx Over a year ago

I am a bit confused now, It wasn't working in my case, That means there must be another point I am missing. I will check it out. Tnx, for showing me the demo.

Starx Over a year ago

Are you sure the encoded JSON from PHP, is exactly like that in you fiddle?

Felix Kling Over a year ago

@Starx: I copy and pasted it from codepad.org/jUiDCeq6. But nevertheless, make sure that your server is generating the right JSON.

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