Replace column values in python

Question

This is hopefully an easy question for someone out there:

I have one data frame that looks like this:

import pandas as pd
names_raw = {
    'device_id': [ '1d28d33a-c98e-4986-a7bb-5881d222c9a8','54322099-e76d-4986-afd2-0861e2113a16','ec3a9f9d-8e4d-4986-bea8-c17c361366e9','cc8e247d-4e2e-4986-b783-e516d03a358c','ca2d8769-ccf5-4986-8aed-741ca68e94cd','12178e22-6d64-4986-966a-374326fdaf3d','50ba7a2e-a1aa-4986-86a7-08e0605dc702','f427c8e9-65d4-46de-b986-8f8e79242842','cee68e2b-135f-45b0-be4b-7c23009866ba','e785988e-2693-47ad-9899-0049860ccaa7','a1986866-13f8-4dbe-b661-8c9f78eac745','a9998ecd-9fe9-4932-870d-29c6b5df1214','9b88e362-b06d-4317-96f5-f266c986a8d6','a04498ef-fd7c-4aa4-bffc-9158ccbad3a1'],
    'pod_id': ['B00001','B00011','B00013','B00016','B00021','B00023','B00024','B00026','B00027','B00028','B00030','B00032','B00034','B00039'],
    'native_id': ['zim_pod_0001','zim_pod_0002',    'zim_pod_0003', 'zim_pod_0004', 'zim_pod_0005', 'zim_pod_0006', 'zim_pod_0007', 'zim_pod_0008', 'zim_pod_0009', 'zim_pod_0010', 'zim_pod_0011', 'zim_pod_0012', 'zim_pod_0013','zim_pod_0014']
    }
names = pd.DataFrame(names_raw, columns = ['device_id', 'pod_id', 'native_id'])

And another data frame that looks like this:

>>> df
                          device_id      day  month  year  rain
0  1d28d33a-c98e-4986-a7bb-5881d222c9a8   31     12  2016   0.0
1  54322099-e76d-4986-afd2-0861e2113a16   31     12  2016   0.0
2  ec3a9f9d-8e4d-4986-bea8-c17c361366e9   31     12  2016   0.0
3  cc8e247d-4e2e-4986-b783-e516d03a358c   31     12  2016   1.2
4  ca2d8769-ccf5-4986-8aed-741ca68e94cd   31     12  2016   2.2
5  12178e22-6d64-4986-966a-374326fdaf3d   31     12  2016   0.2
6  9b88e362-b06d-4317-96f5-f266c986a8d6   31     12  2016   0.0

I want to replace the device_id column with the native_id column. How can this be done using the least amount of lines of code?

The final data frame should look something like this:

>>> df
                           native_id      day  month  year  rain
0                          zim_pod_0001   31     12  2016   0.0
1                          zim_pod_0002   31     12  2016   0.0
2                          zim_pod_0003   31     12  2016   0.0

etc. etc...

MaxU - stand with Ukraine · Accepted Answer · 2017-01-04 21:07:49Z

1

Try this:

df['native_id'] = df.device_id.map(names.set_index('device_id')['native_id'])

Or if you don't want to preserve device_id column in the df DF:

In [210]: df['native_id'] = df.pop('device_id').map(names.set_index('device_id')['native_id'])

In [211]: df
Out[211]:
   day  month  year  rain     native_id
0   31     12  2016   0.0  zim_pod_0001
1   31     12  2016   0.0  zim_pod_0002
2   31     12  2016   0.0  zim_pod_0003
3   31     12  2016   1.2  zim_pod_0004
4   31     12  2016   2.2  zim_pod_0005
5   31     12  2016   0.2  zim_pod_0006
6   31     12  2016   0.0  zim_pod_0013

edited Jan 4, 2017 at 21:07

answered Jan 4, 2017 at 21:05

MaxU - stand with Ukraine

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MaxU - stand with Ukraine Over a year ago

@JAG2024, glad i could help :)

RedVII · Accepted Answer · 2017-01-04 22:12:21Z

0

Use the merge() method which is built-in to Pandas. It essentially works as a join, and is quite straightforward to use. Specify device_id as the joining key, and then select the columns that you want, like so:

df2 = pd.merge(df,names,on="device_id")[["native_id","day","month","year","rain"]]

Result:

      native_id  day  month  year  rain
0  zim_pod_0001   31     12  2016   0.0
1  zim_pod_0002   31     12  2016   0.0
2  zim_pod_0003   31     12  2016   0.0
3  zim_pod_0004   31     12  2016   1.2
4  zim_pod_0005   31     12  2016   2.2
5  zim_pod_0006   31     12  2016   0.2
6  zim_pod_0013   31     12  2016   0.0

answered Jan 4, 2017 at 22:12

RedVII

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