How to create an array with a simple for loop?

Question

I need to create an array that looks like this:

[0,0,1,1,2,2,3,3,4,4....]

Given my following code, how can I eliminate the counter?

int[] SomeArray = new int[24];
int counter = 0;
for(int x = 0 ; x < SomeArray.length-1 ; x++){
    SomeArray[x] = counter;
    SomeArray{x+1] = counter;
    counter++;
}

Current code only increase x by one step, so the output should be 0 1 2 3 4 5 6 .... — user6018651
– user6018651, Commented Dec 7, 2016 at 3:00

Elliott Frisch · Accepted Answer · 2016-12-07 01:13:12Z

3

In Java 8+, you could use an IntStream.range(int, int) and map each value as desired. Something like,

int[] someArray = IntStream.range(0, 24).map(x -> {
    return x / 2;
}).toArray();

Also, please follow Java variable naming conventions (someArray, not SomeArray).

If you have to use Java 7 (or earlier), then you can do it with something like

int[] someArray = new int[24];
for (int i = 0; i < someArray.length; i++) {
    someArray[i] = i / 2;
}

edited Dec 7, 2016 at 1:13

answered Dec 7, 2016 at 1:01

Elliott Frisch

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2 Comments

dudi hisine Over a year ago

Im using android studio so i need to use Java 6.

Elliott Frisch Over a year ago

@דודיחיסין Edited. Next time, for better help faster, include relevant details like that in your question.

hasham.98 · Accepted Answer · 2016-12-07 17:02:55Z

1

use increment x=x+2 as two indexes of array are being stored in every iteration

for(int x = 0 ; x < SomeArray.length-1 ; x+=2){
        SomeArray[x] = x/2;

        SomeArray[x+1] = x/2;
}

answered Dec 7, 2016 at 17:02

hasham.98

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