PHP check variable if exists in array of json

You may try Laravel's Collection::contains method, for example:

$collection = collect(json_decode($jsonString, true));

if ($collection->contains(1) {
    // Exists...
}

Also, you may use key/value pair like this:

if ($collection->contains('ID', 1) {
    //...
}

Also, if you want to get that item from the collection then you may try where like this:

$id = $collection->where('ID', 1)->first(); // ['ID' => 1]

You have a json formatted array and you need to decode it using json_decode first. After that loop the array to check for the id that you want.

So the code should look like this:

$json = '[{"ID":1},{"ID":2}]';
$id = 1;

$data = json_decode($json, true);
foreach($data as $item){
   if($item['id'] == $id) {
      echo 'it exists';
   }
}

Iterate the array using for loop and use the value as a param to json_decode.

$id = 1;
$arr = array('{"ID":1}', '{"ID":2}');
foreach($arr as $val) {
  if (in_array($id, json_decode($val, TRUE))) {
    echo "id present";
  }
}

Try this, if value is exist it will give key of array

$jsondata = '[{"ID":1},{"ID":2}]';
$array = json_decode($jsondata,true);

$key = array_search(1, array_column($array, 'ID'));

Just check if the string is in the json array, with little computation.

I think it's the more efficient way. Check the result here.

<?php
$id = 1;
$array = ['{"ID":1}', '{"ID":2}'];
echo in_array(json_encode(["ID" => $id]), $array) ? 'Yes' : 'No';