I want to declare an array inside a structure with a predefined constant size, but it gives me this error : expected a ']'.
#define MAX_SZAMJEGY 200;
struct szam {
int szj[MAX_SZAMJEGY];
bool negative;
};
3 Answers
Macro expands to
int szj[200;];
which is not valid C++ code.
remove ; from #define MAX_SZAMJEGY 200;
Comments
A preferred C++ solution is to use constants rather than macros. This way you will not have a semicolon problem, and it comes with tons of other benefits as well. Here is how:
(C++ 98):
static const size_t MAX_SZAMJEGY 200;
struct szam {
int szj[MAX_SZAMJEGY];
bool negative;
};
(C++11)
static constexpr size_t MAX_SZAMJEGY=200;
struct szam {
int szj[MAX_SZAMJEGY];
bool negative;
};
And while you are on it, and if you are using C++11, you might as well replace C-style array with C++ std::array. While it doesn't make too much of a difference, it is slightly more convenient to use.
Comments
try
#define MAX_SZAMJEGY 200
instead of
#define MAX_SZAMJEGY 200;
(the semicolon enters the macro)
constexpr std::size_t MAX_SZAMJEGY = 200;