Json.Net serialize/deserialize Class Name attribute C#

Question

Sorry for the (maybe) trivial question but, I'm trying to consume a web service where the entities and my data model classes are named different.

I want to keep my model .Net Class name and use a Json Attribute name to map, serializer/deserializer, with the corresponding web service entity. For example:

Web Service Entity:

"People"

My Model Class:

"Employee"

What I've already do:

[JsonObject(Title="People")]
public class Employee 
{

   [JsonProperty("DifferentPropertyName")]
   string propertyName1 { get; set; }
}

But the json serializer/Deserializer continues to use the .Net class name and I need to set the jsonObject Title.

There is a way to achieve it?

EDIT

I'm working on a Xamarin Forms app, using Simple.OData.Client to consume an OData Service

Thanks

Maybe this will help : stackoverflow.com/questions/13839426/… — Yanga
– Yanga, Commented Nov 25, 2016 at 15:40
Maybe this can help: [JsonProperty(Title="People")] public string propertyName1{get; set;} — Mario Galván
– Mario Galván, Commented Nov 25, 2016 at 18:31
Please show serialization/deserialization code that is doing the wrong thing. — DavidS
– DavidS, Commented Nov 25, 2016 at 18:46
Thanks... The problem is not with the properties but with the class name. As I'm using the simple.odata.client nuget package I'm trying to deserialize a resource entity that is named "People" into a .net class (model) named "Employee". At this point the simple.odata.client looks for a service resource (entity) named "Employee" that can't be found. — Richard
– Richard, Commented Nov 25, 2016 at 19:05
Have you tried serializing to JSON string first then deserializing that string into you Employee class? Might not be good for performance but it's a workaround. — Christian Melendez
– Christian Melendez, Commented Nov 26, 2016 at 15:50

Thibault · Accepted Answer · 2018-03-07 08:32:04Z

6

DataContractAttribute may be your solution.

public class RichFilter
{
   public Trolo item { get; set; }
}
[DataContract(Name = "item")]
public class Trolo 
{ 
   public string connector { get; set; } 
}

If you serialize a RichFilter object, here is the output :

{"item":{"connector":"AND"}}

answered Mar 7, 2018 at 8:32

Thibault

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2 Comments

Erik Philips Over a year ago

When using the DataContractAttribute you must also specify the DataMemberAttribute on properties you want to serialize.

Richard Over a year ago

Since I was using Simple.OData.Client, that is not able to recognize the DataContract attribute, I had to pass the name of my remote element explicitly. I, anyway, used a custom attribute like "ClassName" with a property that returns the name of the class but this is too much work for its purpose.

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