for (int j = 0; j <= l - 1; j++)
{ char c1 = str.charAt(j);
n[j] = c1;
}
//It is showing error-arrayIndexoutofbounds
'str' is an inputted string and 'l' is the length of the string str. I have to store all its character in an array and the array 'n' is of char type I have tried to store it by for loop but its showing error . Please help me out. Just remove that equal to sign in ur loop it will only be less than
Your array n should be declared as:
char[] n = new char[str.length()];
That creates an array with the exact size needed to put all your String's characters in it.
An ArrayIndexOutOfBoundsException is thrown when you access an illegal index of the array, in this case I suspect your array is smaller than the length of the String.
char[] n = new char[l]. (<- that's a lower-case L, not the digit "one")
char types to represent character arrays (yes it's too bad but Unicode outgrew 16-bit only after Java already had comitted to it). Instead, make an array of int and use codePointAt and codePointCount etc.No need to create and fill such an array manually, there is a built-in method String.toCharArray that does the job for you:
n = str.toCharArray()
If you want to convert string into character array then string class already have method called toCharArray().
String str = "StackOverflow";
char[] charArray = str.toCharArray();
then if you want to check content of array print it.
for(int i = 0;i < charArray.length ; i++) {
System.out.print(" " + charArray[i]);
}
System.out.println(Arrays.toString(charArray));
n?