JSON: key value concatenation in javascript

Question

I'm trying to parse json object to get the key and value concatenated to a variable. My desired output from the given json is:

"/" - 7.84 GiB; "/opt" - 4.86 GiB; "/usr" - 4.80 GiB

Using my snippet i can get objects but struggling to get the name and value in desired format. Please assist.

for (i = 0; i < obj.length; i++) 
{
 if  ( obj[i].name === 'mountpoints') 
 {
 js_mountpoints = obj[i].value;
 break;
 }
 js_mountpoints = 'NA';
}

My JSON input:

[{
    "name" : "pe_build",
    "value" : "2016.2.1"
}, 
{
    "name" : "kernel",
    "value" : "Linux"
}, {
    "name" : "blockdevices",
    "value" : "sda,sdb,sr0"
},
{
    "name" : "mountpoints",
    "value" : {
        "\/boot\/efi" : {
            "size_bytes" : 261861376,
            "size" : "249.73 MiB",
            "capacity" : "0%"
        },
        "\/opt" : {
            "size_bytes" : 2086666240,
            "size" : "1.94 GiB",
            "capacity" : "1.64%"
        },
        "\/boot" : {
            "size_bytes" : 258650112,
            "size" : "246.67 MiB",
            "capacity" : "74.28%"
        },
        "\/var" : {
            "size_bytes" : 10475274240,
            "size" : "9.76 GiB",
            "filesystem" : "xfs",
            "capacity" : "4.01%"
        }
    }
    },  {
    "name" : "uptime_seconds",
    "value" : 244181
}, {
"name" : "memoryfree",
"value" : "6.66 GiB"
}, {
"name" : "memoryfree_mb",
"value" : 6816.91796875
}
]

Your for loop will iterate over outer values of Json. You need to another iterate inside data object. Also once you reach desired key, you will need to pull size from that object. — Pratik Gaikwad
– Pratik Gaikwad, Commented Nov 8, 2016 at 0:03

Jakk · Accepted Answer · 2016-11-08 06:08:46Z

1

finalStr = ''
Object.keys(obj).forEach(function(key) {
  if (obj[key].name === 'mountpoints') { // only get sizes for mountpoints
    var value = obj[key].value;
    Object.keys(value).forEach(function(name) { // add all sizes to string
      finalStr += '"' + name + '" - ' + value[name].size + ';';
    }); //update
  }
}); //update

if (finalStr.length > 0) { // at least one entry was added
  finalStr.slice(0, -1);
}

edited Nov 8, 2016 at 6:08

Jakk

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answered Nov 8, 2016 at 3:30

Dec Sander

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