how to replace result urls using regex php

Question

i want to parser web using simple dom ,i get output like here

my code

foreach($html->find('ul[class=result-topic] a ') as $e){
  $count++;


 $d = ($e->href )."<br>";




echo($d)."<br>";
if($count == 2)
{
    exit();
}
}

output

/news/354985850
/film/74808409409

this not full article ,how to replace url with full article like here ,output

/news/full/354985850
/film/full/74808409409

how to insert 'full' after category(news,film...etc) ,before post id(354985850,74808409409,....etc) — dexter
– dexter, Commented Oct 31, 2016 at 0:17

chris85 · Accepted Answer · 2016-10-31 00:30:07Z

2

One way would be to explode, append the second to last element, then implode.

$string = '/news/354985850';
$parts = explode('/', $string);
$parts[(count($parts) - 1)] = 'full/' . $parts[(count($parts) - 1)]; 
echo implode('/', $parts);

Demo: https://eval.in/669122

Another approach would be a regex with preg_replace:

$string = '/news/354985850';
echo preg_replace('~(.*)/~', '$1/full/', $string);

Demo: https://eval.in/669123

Regex Demo: https://regex101.com/r/dQJY8v/1

edited Oct 31, 2016 at 0:30

answered Oct 31, 2016 at 0:27

chris85

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