Filter a multi dimensional JS array using a keyword [duplicate]

Question

I have an array that looks like this:

[['place', '1', '-2'],['place2', '1', '-2'],['place3', '1', '-3']]

I want to filter it using a keyword from onClick so it looks like this:

[['place', '1', '-2'],['place2', '1', '-2']]

If my filter is for example -2.

The code i'm using now is (where object is the variable being filtered):

return $.map(object, function (item, key) {
   if (item[0] === value) {
       return item;
   }
});

And then I call it using:

var markers = results(filter);

But the result I get is blank.

Hopefully I am making sense if not I am very sorry please let me know and I can try to clarify.

If your value to be filtered appears anywhere in array you can also use index of on inner array in addition to answers given. But it might not work on older browsers. — Shailesh Vaishampayan
– Shailesh Vaishampayan, Commented Oct 22, 2016 at 20:34
@ShaileshVaishampayan my goal is to have a filter for [1] [0] [2] — Karim
– Karim, Commented Oct 22, 2016 at 20:41

Nina Scholz · Accepted Answer · 2016-10-22 21:21:36Z

0

You could use Array#filter for it and return the filtered items.

var data = [['place', '1', '-2'], ['place2', '1', '-2'], ['place3', '1', '-3']],
    filtered = data.filter(function (a) {
        return a[2] === '-2';
    });

console.log(filtered);

Search for any item with the given string

var data = [['place', '1', '-2'], ['place2', '1', '-2'], ['place3', '1', '-3']],
    filtered = data.filter(function (a) {
        return a.some(function (b) {
            return b === '-2';
        });
    });

console.log(filtered);

ES6, Search for any item with the given string

var data = [['place', '1', '-2'], ['place2', '1', '-2'], ['place3', '1', '-3']],
    filtered = data.filter(a => a.some(b => b === '-2'));

console.log(filtered);

edited Oct 22, 2016 at 21:21

answered Oct 22, 2016 at 20:29

Nina Scholz

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4 Comments

Karim Over a year ago

This could work I will give it a try thanks

Karim Over a year ago

This almost works. One issue I am having is return a[3] === 'text'; works while return a[3] === filterfromfunction; does not any idea?

Nina Scholz Over a year ago

please add the content of filterfromfunction.

Karim Over a year ago

I ended up making a global variable and that worked

FlatLander · Accepted Answer · 2016-10-22 20:28:25Z

0

Try this

    var places = [['place', '1', '-2'],['place2', '1', '-2'],['place3', '1', '-3']]
    var result = places.filter(place => place[2] === '-2')

    console.log(result) // [['place', '1', '-2'],['place2', '1', '-2']]

answered Oct 22, 2016 at 20:28

FlatLander

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