PHP - array_diff One multidimensional array and one flat array

Question

I have two arrays. One of them is a multidimensional array e.g.

 $products = array(
        0 => array(
            'product_id' => 33,
            'variation_id' => 0,
            'product_price' => 500.00
        ),
        1 => array(
            'product_id' => 45,
            'variation_id' => 0,
            'product_price' => 600.00
        ),
2 => array(
            'product_id' => 48,
            'variation_id' => 0,
            'product_price' => 600.00
        ),
        3 => array(
            'product_id' => 49,
            'variation_id' => 0,
            'product_price' => 600.00
        )
    );

and I have a flat array

$missingItems= array(49,33);

I would like to remove items from $products where their product_id is in the array missingItems string.

$diff = array();
foreach ($missingItems as $missingItem) {
    foreach ($products as $product) {
        if($missingItem != $product['product_id']){
            $diff[] = $missingItem;
        }       
    }   
}
echo '<pre>';
print_r($diff);
echo '</pre>';

When I do this, all the values are being repeated multiple times. e.g. if I have 4 items in my first array, and two in my second. There are 8 results. I would like only 2 to appear i.e. those that are not present in the second array.

When I have two flat arrays I use array_diff but I'm not sure how to use it in this case where I have a multidimensional array and a flat array.

In your output array, should it return a multi dimensional array with main keys 1 and 2? And remove 0 and 3? — Indrasis Datta
– Indrasis Datta, Commented Sep 13, 2016 at 11:35

Alexey Chuhrov · Accepted Answer · 2016-09-13 11:35:54Z

7

Use array_filter():

$filtered = array_filter($products, function($product) use ($missingItems){
    return !in_array($product['product_id'], $missingItems);
});

answered Sep 13, 2016 at 11:35

Alexey Chuhrov

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Comments

Sathish · Accepted Answer · 2016-09-13 11:35:45Z

1

you can use in_array() to check and make new array

$diff = array();
foreach ($products as $product) {
  if(!in_array($product['product_id'], $missingItems)){
    $diff[] = $product;
  }  
}
echo '<pre>';
print_r($diff);
echo '</pre>';

I hope this will help to achieve your goal

answered Sep 13, 2016 at 11:35

Sathish

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Comments

Keyur Mistry · Accepted Answer · 2016-09-13 11:36:46Z

0

Use in_array()

$diff = array();
foreach ($products as $product) {
  if(!in_array($product['product_id'], $missingItems)){
    $diff[] = $product;
  }  
}

answered Sep 13, 2016 at 11:36

Keyur Mistry

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Comments

Community · Accepted Answer · 2020-06-20 09:12:55Z

0

There's no need to unnecessarily traverse through your $missingItems array.

in_array() does the trick.

foreach ($products as $k => $product) {
    if (in_array($product['product_id'], $missingItems)) {
        unset($products[$k]);
    }       
}

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Sep 13, 2016 at 11:37

Indrasis Datta

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