How to sort integer array in golang using default sort function

Question

A stupid question. I can't sort using default sort function in go

package main
import "fmt"
import "sort"

func main() {
    var arr [5]int
    fmt.Println("Enter 5 elements")
    for i:=0;i<5;i++{
        fmt.Scanf("%d",&arr[i])
    }
    sort.Ints(arr)
    fmt.Println(arr)
}

When executing the above program, It throws out

cannot use arr (type [5]int) as type []int in argument to sort.Ints

Need Help.

sort.Ints takes a slice, not an array.

sberry
– sberry

2016-08-30 04:45:43 +00:00
Commented Aug 30, 2016 at 4:45 — sberry
– sberry, Commented Aug 30, 2016 at 4:45

sberry · Accepted Answer · 2016-08-30 04:48:17Z

34

sort.Ints expects a slice of int, not an array. Easiest fix is to change

sort.Ints(arr)

to

sort.Ints(arr[:])

answered Aug 30, 2016 at 4:48

sberry

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4 Comments

Jose Thomas Over a year ago

What change is arr[:] actually making?

sberry Over a year ago

@JoseThomas: read over this blog.golang.org/go-slices-usage-and-internals.

Jose Thomas Over a year ago

What is the complexity of this default sort function?

sberry Over a year ago

There is no "default sort function" as far as sorting algorithm used. Go uses different algorithms based on some criteria. You can read through them in the comments or by following along the code here: golang.org/src/sort/sort.go

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