Create random numpy matrix of same size as another.

Question

This question here was useful, but mine is slightly different.

I am trying to do something simple here, I have a numpy matrix A, and I simply want to create another numpy matrix B, of the same shape as A, but I want B to be created from numpy.random.randn() How can this be done? Thanks.

Graham · Accepted Answer · 2017-09-27 04:42:39Z

52

np.random.randn takes the shape of the array as its input which you can get directly from the shape property of the first array. You have to unpack a.shape with the * operator in order to get the proper input for np.random.randn.

a = np.zeros([2, 3])
print(a.shape)
# outputs: (2, 3)
b = np.random.randn(*a.shape)
print(b.shape)
# outputs: (2, 3)

edited Sep 27, 2017 at 4:42

Graham

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answered Aug 9, 2016 at 20:47

Chris Mueller

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3 Comments

TheGrapeBeyond Over a year ago

Thanks! But what's with the '*'?

Chris Mueller Over a year ago

@TheGrapeBeyond It unpacks the arguments. Have a look at this question.

TheGrapeBeyond Over a year ago

Very interesting. Thanks, TIL.

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