2

I want to get some data from my user. So first, I use a controller to create a view which receives a Model:

public ViewResult CreateArticle()
{
    Article newArticle = new Article();
    ImagesUploadModel dataFromUser = new ImagesUploadModel(newArticle);
    return View(dataFromUser);
}

Then, I have the view:

<asp:Content ID="Content1" ContentPlaceHolderID="MainContentPlaceHolder" runat="server">

    <h2>AddArticle</h2>

    <% using (Html.BeginForm("CreateArticle", "Admin", FormMethod.Post, new { enctype = "multipart/form-data" })){ %>


                <%= Html.LabelFor(model => model.newArticle.Title)%>
                <%= Html.TextBoxFor(model => model.newArticle.Title)%>
   
                <%= Html.LabelFor(model => model.newArticle.ContentText)%>
                <%= Html.TextBoxFor(model => model.newArticle.ContentText)%>

                <%= Html.LabelFor(model => model.newArticle.CategoryID)%>
                <%= Html.TextBoxFor(model => model.newArticle.CategoryID)%>

                <p>
                    Image1: <input type="file" name="file1" id="file1" />
                </p>
                <p>
                    Image2: <input type="file" name="file2" id="file2" />
                </p>

            <div>
                <button type="submit" />Create
            </div>



    <%} %>


</asp:Content>

and finally - the original controller, but this time configured to accept the data:

   [HttpPost]
    public ActionResult CreateArticle(ImagesUploadModel dataFromUser)
    {
        if (ModelState.IsValid)
        {
            HttpPostedFileBase[] imagesArr;
            imagesArr = new HttpPostedFileBase[2]; 
            int i = 0;
            foreach (string f in Request.Files)
            {
                HttpPostedFileBase file = Request.Files[f];
                if (file.ContentLength > 0)
                    imagesArr[i] = file;
            }

The rest of this controller does not matter since no matter what I do, the count attribute of Request.Files (or Request.Files.Keys) remains 0. I simply can't find a way to pass the files from the form (the Model passes just fine).

1

2 Answers 2

3

You might want to consider not posting the files with the rest of the form- there are good reasons and other ways you can achieve what you want.

Also, check out this question and this advice regarding file uploads in MVC.

Sign up to request clarification or add additional context in comments.

2 Comments

Well, I guess I'll just split it up into 2 views then :-P thanks.
It could even be the same view with two forms in it (another way to achieve the "2 step process").
3

You could add the files to your view model:

public class ImagesUploadModel
{
    ...
    public HttpPostedFileBase File1 { get; set; }
    public HttpPostedFileBase File2 { get; set; }
}

And then:

[HttpPost]
public ActionResult CreateArticle(ImagesUploadModel dataFromUser)
{
    if (ModelState.IsValid)
    {
        // Use dataFromUser.File1 and dataFromUser.File2 directly here
    }
    return RedirectToAction("index");
}

5 Comments

that would be an awesome solution, but how do I update the model data in the view. that is - how does the upload mechanism work (what replaces <input type="file" name="file1" id="file1" /> ?)
There's no HTML helper built into ASP.NET MVC currently that allows you to generate file inputs. You need to generate them manually or use one of the helpers in MVCContrib.
Well, I guess I'll just split it up into 2 views then :-P thanks.
@DarinDimitrov Got error:- No MediaTypeFormatter is available to read an object of type 'CommentModel' from content with media type 'multipart/form-data'
@ujjaval, you seem to be attempting to use this in a Web API controller action. My answer is about ASP.NET MVC.

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.